Determina, usando a calculadora

Ainda os números: Matematicamente Falando 8 - Parte 1 Pág. 115 Ex. 33

Enunciado
Determina, usando a calculadora e apresentando o resultado em notação científica:

  1. $3,7\times {{10}^{29}}-7,4\times {{10}^{30}}$
  2. $5,02\times {{10}^{-27}}+7,89\times {{10}^{-26}}$
  3. $(4,5\times {{10}^{13}})\div (1,5\times {{10}^{-21}})$
  4. $1,025\times {{10}^{17}}\times 8,2\times {{10}^{-2}}$

Resolução

  1. ­
    $\begin{array}{*{35}{l}}
    3,7\times {{10}^{29}}-7,4\times {{10}^{30}} & = & 0,37\times {{10}^{30}}-7,4\times {{10}^{30}}  \\
    {} & = & (0,37-7,4)\times {{10}^{30}}  \\
    {} & = & -7,03\times {{10}^{30}}  \\
    \end{array}$

  2. ­
    $\begin{array}{*{35}{l}}
    5,02\times {{10}^{-27}}+7,89\times {{10}^{-26}} & = & 5,02\times {{10}^{-27}}+78,9\times {{10}^{-27}}  \\
    {} & = & (5,02+78,9)\times {{10}^{-27}}  \\
    {} & = & 83,92\times {{10}^{-27}}  \\
    {} & = & 8,392\times {{10}^{-26}}  \\
    \end{array}$

  3. ­
    $\begin{array}{*{35}{l}}
    (4,5\times {{10}^{13}})\div (1,5\times {{10}^{-21}}) & = & \frac{4,5\times {{10}^{13}}}{1,5\times {{10}^{-21}}}  \\
    {} & = & \frac{4,5}{1,5}\times \frac{{{10}^{13}}}{{{10}^{-21}}}  \\
    {} & = & 3\times {{10}^{34}}  \\
    \end{array}$

  4. ­
    $\begin{array}{*{35}{l}}
    1,025\times {{10}^{17}}\times 8,2\times {{10}^{-2}} & = & (1,025\times 8,2)\times ({{10}^{17}}\times {{10}^{-2}})  \\
    {} & = & 8,405\times {{10}^{15}}  \\
    \end{array}$

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