{"id":9588,"date":"2012-09-30T00:36:49","date_gmt":"2012-09-29T23:36:49","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=9588"},"modified":"2021-12-13T00:44:37","modified_gmt":"2021-12-13T00:44:37","slug":"decompoe-os-numeros","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=9588","title":{"rendered":"Decomp\u00f5e os n\u00fameros"},"content":{"rendered":"<p><ul id='GTTabs_ul_9588' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_9588' class='GTTabs_curr'><a  id=\"9588_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_9588' ><a  id=\"9588_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_9588'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Decomp\u00f5e os n\u00fameros $ &#8211; 20$ e $12$ num produto de tr\u00eas fatores em que, pelo menos, um deles \u00e9 um n\u00famero inteiro negativo.<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_9588' onClick='GTTabs_show(1,9588)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_9588'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><\/p>\n<blockquote>\n<p>O produto de dois n\u00fameros com o <strong>mesmo sinal<\/strong> \u00e9 um <strong>n\u00famero positivo<\/strong> igual ao produto dos valores absolutos dos fatores. $$\\begin{array}{*{20}{c}} {\\left( { + 3} \\right) \\times \\left( { + 7} \\right) = 21}&amp;{}&amp;{\\left( { &#8211; 9} \\right) \\times \\left( { &#8211; 2} \\right) = 18} \\end{array}$$<\/p>\n<\/blockquote>\n<blockquote>\n<p>O produto de dois n\u00fameros de <strong>sinais diferentes<\/strong> \u00e9 um <strong>n\u00famero negativo<\/strong> cujo valor absoluto \u00e9 igual ao produto dos valores absolutos dos fatores. $$\\begin{array}{*{20}{c}} {\\left( { + 4} \\right) \\times \\left( { &#8211; 5} \\right) =\u00a0 &#8211; 20}&amp;{}&amp;{\\left( { &#8211; 6} \\right) \\times \\left( { + 4} \\right) =\u00a0 &#8211; 24} \\end{array}$$<\/p>\n<\/blockquote>\n<p>Por exemplo: $$\\begin{array}{*{20}{c}} { &#8211; 20 = 2 \\times ( &#8211; 2) \\times 5}&amp;{}&amp;{ &#8211; 20 =\u00a0 &#8211; 4 \\times 1 \\times 5}&amp;{}&amp;{ &#8211; 20 =\u00a0 &#8211; 2 \\times ( &#8211; 2) \\times \\left( { &#8211; 5} \\right)} \\end{array}$$<\/p>\n<p>\u00a0Verifica\u00e7\u00e3o: $$\\begin{array}{*{20}{c}} {\\begin{array}{*{20}{l}} {2 \\times ( &#8211; 2) \\times 5}&amp; = &amp;{ &#8211; 4 \\times 5}\\\\ {}&amp; = &amp;{ &#8211; 20} \\end{array}}&amp;{}&amp;{\\begin{array}{*{20}{l}} { &#8211; 4 \\times 1 \\times 5}&amp; = &amp;{ &#8211; 4 \\times 5}\\\\ {}&amp; = &amp;{ &#8211; 20} \\end{array}}&amp;{}&amp;{\\begin{array}{*{20}{l}} { &#8211; 2 \\times ( &#8211; 2) \\times \\left( { &#8211; 5} \\right)}&amp; = &amp;{4 \\times \\left( { &#8211; 5} \\right)}\\\\ {}&amp; = &amp;{ &#8211; 20} \\end{array}} \\end{array}$$<\/p>\n<\/p>\n<p>Por exemplo:\u00a0$$12\\begin{array}{*{20}{c}} { = 2 \\times ( &#8211; 3) \\times \\left( { &#8211; 2} \\right)}&amp;{}&amp;{12 =\u00a0 &#8211; 4 \\times 1 \\times \\left( { &#8211; 3} \\right)}&amp;{}&amp;{12 =\u00a0 &#8211; 2 \\times ( &#8211; 2) \\times 3} \\end{array}$$<\/p>\n<p>\u00a0Verifica\u00e7\u00e3o: $$\\begin{array}{*{20}{c}} {\\begin{array}{*{20}{l}} {2 \\times ( &#8211; 3) \\times \\left( { &#8211; 2} \\right)}&amp; = &amp;{ &#8211; 6 \\times \\left( { &#8211; 2} \\right)}\\\\ {}&amp; = &amp;{12} \\end{array}}&amp;{}&amp;{\\begin{array}{*{20}{l}} { &#8211; 4 \\times 1 \\times \\left( { &#8211; 3} \\right)}&amp; = &amp;{ &#8211; 4 \\times \\left( { &#8211; 3} \\right)}\\\\ {}&amp; = &amp;{12} \\end{array}}&amp;{}&amp;{\\begin{array}{*{20}{l}} { &#8211; 2 \\times ( &#8211; 2) \\times 3}&amp; = &amp;{4 \\times 3}\\\\ {}&amp; = &amp;{12} \\end{array}} \\end{array}$$<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_9588' onClick='GTTabs_show(0,9588)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Decomp\u00f5e os n\u00fameros $ &#8211; 20$ e $12$ num produto de tr\u00eas fatores em que, pelo menos, um deles \u00e9 um n\u00famero inteiro negativo. Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o O produto de dois&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":19296,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[317,97,318],"tags":[428,320,319],"series":[],"class_list":["post-9588","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-7-o-ano","category-aplicando","category-numeros-inteiros","tag-7-o-ano","tag-multiplicacao","tag-numeros-inteiros-2"],"views":2196,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat86.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/9588","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=9588"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/9588\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19296"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=9588"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=9588"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=9588"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=9588"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}