\nEnunciado<\/b><\/span><\/p>\n
Determine as solu\u00e7\u00f5es das seguintes equa\u00e7\u00f5es:<\/p>\n
\n
${x^3} + 5x = 0$<\/li>\n
${x^2} + 4x + 7 = 0$<\/li>\n<\/ol>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
\n
Ora,
\n$$\\begin{array}{*{20}{l}}
\n{{x^3} + 5x = 0}& \\Leftrightarrow &{x({x^2} + 5) = 0} \\\\
\n{}& \\Leftrightarrow &{\\begin{array}{*{20}{l}}
\n{x = 0}& \\vee &{{x^2} + 5 = 0}
\n\\end{array}} \\\\
\n{}& \\Leftrightarrow &{\\begin{array}{*{20}{l}}
\n{x = 0}& \\vee &{{x^2} =\u00a0 – 5}
\n\\end{array}} \\\\
\n{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}
\n{x = 0}& \\vee &{x =\u00a0 – \\sqrt 5 i}& \\vee &{x = \\sqrt 5 i}
\n\\end{array}}
\n\\end{array}$$<\/li>\n
Ora,
\n$$\\begin{array}{*{20}{l}}
\n{{x^2} + 4x + 7 = 0}& \\Leftrightarrow &{x = \\frac{{ – 4 \\pm \\sqrt {16 – 28} }}{2}} \\\\
\n{}& \\Leftrightarrow &{x = \\frac{{ – 4 \\pm 2\\sqrt { – 3} }}{2}} \\\\
\n{}& \\Leftrightarrow &{\\begin{array}{*{20}{l}}
\n{x =\u00a0 – 2 – \\sqrt 3 i}& \\vee &{x =\u00a0 – 2 + \\sqrt 3 i}
\n\\end{array}}
\n\\end{array}$$<\/li>\n<\/ol>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Determine as solu\u00e7\u00f5es das seguintes equa\u00e7\u00f5es: ${x^3} + 5x = 0$ ${x^2} + 4x + 7 = 0$ Resolu\u00e7\u00e3o >> Resolu\u00e7\u00e3o << Enunciado<\/p>\n","protected":false},"author":1,"featured_media":19576,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[226,97,310],"tags":[427,18],"series":[],"class_list":["post-8917","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-12--ano","category-aplicando","category-numeros-complexos-12--ano","tag-12-o-ano","tag-numeros-complexos"],"views":2623,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat146_b.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/8917","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=8917"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/8917\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19576"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=8917"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=8917"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=8917"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=8917"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}