{"id":8571,"date":"2012-04-19T19:27:04","date_gmt":"2012-04-19T18:27:04","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=8571"},"modified":"2022-01-06T19:22:46","modified_gmt":"2022-01-06T19:22:46","slug":"escreve-uma-equacao-do-2-o-grau","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=8571","title":{"rendered":"Escreve uma equa\u00e7\u00e3o do 2.\u00ba grau"},"content":{"rendered":"<p><ul id='GTTabs_ul_8571' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_8571' class='GTTabs_curr'><a  id=\"8571_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_8571' ><a  id=\"8571_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_8571'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Escreve uma equa\u00e7\u00e3o do 2.\u00ba grau sabendo que:<\/p>\n<ol>\n<li>$S = 3$ e $P = 2$;<\/li>\n<li>$S =\u00a0 &#8211; \\frac{1}{2}$ e $P = \\frac{3}{4}$.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_8571' onClick='GTTabs_show(1,8571)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_8571'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p><strong>Soma e produto das ra\u00edzes de uma equa\u00e7\u00e3o do 2.\u00ba grau<\/strong>: Se ${x_1}$ e ${x_2}$ s\u00e3o as duas ra\u00edzes reais de uma equa\u00e7\u00e3o do 2.\u00ba grau, essa equa\u00e7\u00e3o pode ser escrita na forma $${x^2} &#8211; Sx + P = 0$$ em que $S = {x_1} + {x_2}$ designa a soma das ra\u00edzes e $P = {x_1} \\times {x_2}$ o seu produto. A rela\u00e7\u00e3o permanece v\u00e1lida no caso da equa\u00e7\u00e3o admitir apenas 1 solu\u00e7\u00e3o real. Nesse, caso basta considerar ${x_1} = {x_2}$.<\/p>\n<\/blockquote>\n<ol>\n<li>Como $S = 3$ e $P = 2$, ent\u00e3o uma equa\u00e7\u00e3o que satisfaz o pedido \u00e9: ${x^2} &#8211; 3x + 2 = 0$ (por exemplo). \u00a0 $2{x^2} &#8211; 6x + 4 = 0$ e $ &#8211; 7{x^2} + 21x &#8211; 14 = 0$ s\u00e3o tamb\u00e9m respostas\u00a0poss\u00edveis. (Porqu\u00ea?)<br \/>\n\u00ad<\/li>\n<li>\u00a0Como $S =\u00a0 &#8211; \\frac{1}{2}$ e $P = \\frac{3}{4}$, ent\u00e3o uma equa\u00e7\u00e3o que satisfaz o pedido \u00e9:\u00a0${x^2} + \\frac{1}{2}x + \\frac{3}{4} = 0$ (por exemplo).<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_8571' onClick='GTTabs_show(0,8571)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Escreve uma equa\u00e7\u00e3o do 2.\u00ba grau sabendo que: $S = 3$ e $P = 2$; $S =\u00a0 &#8211; \\frac{1}{2}$ e $P = \\frac{3}{4}$. Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":14083,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,303],"tags":[426,306],"series":[],"class_list":["post-8571","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-equacoes-do-2-o-grau","tag-9-o-ano","tag-equacao-do-2-o-grau"],"views":4386,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/Mat28.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/8571","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=8571"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/8571\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/14083"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=8571"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=8571"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=8571"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=8571"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}