\n| \u00a0Varia\u00e7\u00e3o de $g$<\/td>\n | $ – 20 + 10\\ln 10$<\/td>\n | $ \\nearrow $<\/td>\n | $100{e^{ – 3}}$<\/td>\n | $ \\searrow $<\/td>\n | $ – 2 + \\ln 100$<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n $$g(10) = 100 \\times \\frac{{\\ln 10 – 2}}{{10}} =\u00a0 – 20 + 10\\ln 10 \\approx 3,0$$
\n$$g({e^3}) = 100 \\times \\frac{{\\ln {e^3} – 2}}{{{e^3}}} = 100 \\times \\frac{1}{{{e^3}}} = 100{e^{ – 3}} \\approx 5,0$$
\n$$g(100) = 100 \\times \\frac{{\\ln 100 – 2}}{{100}} =\u00a0 – 2 + \\ln 100 \\approx 2,6$$
\n$${e^3} \\approx 20,1$$<\/p>\n A m\u00e1xima capacidade pulmonar \u00e9, aproximadamente, 5,0 litros, atingindo-se cerca dos 20 anos de idade.
\n\u00ad<\/li>\n<\/ol>\n |