{"id":7343,"date":"2012-01-19T18:53:22","date_gmt":"2012-01-19T18:53:22","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=7343"},"modified":"2022-01-14T00:09:46","modified_gmt":"2022-01-14T00:09:46","slug":"duas-funcoes-reais-de-variavel-real","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=7343","title":{"rendered":"Duas fun\u00e7\u00f5es reais de vari\u00e1vel real"},"content":{"rendered":"<p><ul id='GTTabs_ul_7343' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_7343' class='GTTabs_curr'><a  id=\"7343_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_7343' ><a  id=\"7343_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_7343'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Considere as fun\u00e7\u00f5es reais de vari\u00e1vel real $f$ e $g$ definidas por $$\\begin{matrix}<br \/>\nf(x)={{e}^{2x+1}} &amp; {} &amp; {} &amp; g(x)=\\ln \\left( 3-3x \\right)\u00a0 \\\\<br \/>\n\\end{matrix}$$<\/p>\n<ol>\n<li>Qual\u00a0 o dom\u00ednio de cada uma das fun\u00e7\u00f5es?<\/li>\n<li>Defina a fun\u00e7\u00e3o $f\\circ g$ e simplifique o mais poss\u00edvel a express\u00e3o que a representa.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_7343' onClick='GTTabs_show(1,7343)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_7343'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>Considere as fun\u00e7\u00f5es reais de vari\u00e1vel real $f$ e $g$ definidas por $$\\begin{matrix}<br \/>\nf(x)={{e}^{2x+1}} &amp; {} &amp; {} &amp; g(x)=\\ln \\left( 3-3x \\right)\u00a0 \\\\<br \/>\n\\end{matrix}$$<\/p>\n<\/blockquote>\n<p>\u00ad<\/p>\n<ol>\n<li>\u00a0Os dom\u00ednios das fun\u00e7\u00f5es $f$ e $g$ s\u00e3o:<br \/>\n$$\\begin{array}{*{35}{l}}<br \/>\n{{D}_{f}} &amp; = &amp; \\left\\{ x\\in \\mathbb{R}:\\left( 2x+1 \\right)\\in \\mathbb{R} \\right\\}\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\mathbb{R}\u00a0 \\\\<br \/>\n\\end{array}$$<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{D}_{g}} &amp; = &amp; \\left\\{ x\\in \\mathbb{R}:3-3x&gt;0 \\right\\}\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\left] -\\infty ,1 \\right[\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\n\u00ad<\/li>\n<li>Comecemos por determinar o dom\u00ednio de $f\\circ g$:\\[\\begin{array}{*{35}{l}}<br \/>\n{{D}_{f\\circ g}} &amp; = &amp; \\left\\{ x\\in \\mathbb{R}:x\\in {{D}_{g}}\\wedge g(x)\\in {{D}_{f}} \\right\\}\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\left\\{ x\\in \\mathbb{R}:x&lt;1\\wedge (\\ln \\left( 3-3x \\right))\\in \\mathbb{R} \\right\\}\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\left\\{ x\\in \\mathbb{R}:x&lt;1\\wedge x&lt;1 \\right\\}\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\left] -\\infty ,1 \\right[\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\nOra, $$\\begin{array}{*{35}{l}}<br \/>\n(f\\circ g)(x) &amp; = &amp; f(g(x))\u00a0 \\\\<br \/>\n{} &amp; = &amp; f(\\ln \\left( 3-3x \\right))\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{e}^{2\\times (\\ln \\left( 3-3x \\right))+1}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{e}^{2\\times \\ln \\left( 3-3x \\right)}}\\times {{e}^{1}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{e}^{1}}\\times {{e}^{\\ln {{\\left( 3-3x \\right)}^{2}}}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; e\\times {{(3-3x)}^{2}}\u00a0 \\\\<br \/>\n\\end{array}$$<br \/>\nLogo: \\[\\begin{array}{*{35}{l}}<br \/>\nf\\circ g: &amp; \\left] -\\infty ,1 \\right[\\to \\mathbb{R}\u00a0 \\\\<br \/>\n{} &amp; x\\to e\\times {{(3-3x)}^{2}}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<\/ol>\n<p style=\"text-align: center;\"><script 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