{"id":6937,"date":"2011-09-27T23:28:28","date_gmt":"2011-09-27T22:28:28","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=6937"},"modified":"2022-01-16T02:31:42","modified_gmt":"2022-01-16T02:31:42","slug":"uma-caixa-contem-40-chocolates","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=6937","title":{"rendered":"Uma caixa cont\u00e9m 40 chocolates"},"content":{"rendered":"<p><ul id='GTTabs_ul_6937' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_6937' class='GTTabs_curr'><a  id=\"6937_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_6937' ><a  id=\"6937_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_6937'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Uma caixa cont\u00e9m 40 chocolates com a mesma forma e tamanho: 6 s\u00e3o de chocolate com avel\u00e3, 15 de chocolate preto, 10 de chocolate de leite e os restantes de chocolate branco.<\/p>\n<p>Retirando ao acaso um chocolate da caixa, qual a probabilidade de:<\/p>\n<ol>\n<li>ser de chocolate com avel\u00e3?<\/li>\n<li>ser de chocolate de leite?<\/li>\n<li>ser de chocolate branco?<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_6937' onClick='GTTabs_show(1,6937)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_6937'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<p>O espa\u00e7o de resultados desta experi\u00eancia aleat\u00f3ria \u00e9 constitu\u00eddo por 40 elementos, pois existem 40 maneiras distintas de retirar um chocolate da caixa. Assim,\u00a0$NCP=40$.<\/p>\n<ol>\n<li>Relativamente ao acontecimento A: &#8220;ser chocolate com avel\u00e3&#8221;, o n\u00famero de casos favor\u00e1veis \u00e9\u00a0$NCF=6$, pois, contendo a caixa 6 chocolates com avel\u00e3, h\u00e1 seis maneiras distintas de obter um desses chocolates.<br \/>\nLogo, $P(A)=\\frac{6}{40}=\\frac{3}{20}$.<br \/>\n\u00ad<\/li>\n<li>Relativamente ao acontecimento L: &#8220;ser chocolate de leite&#8221;, o n\u00famero de casos favor\u00e1veis \u00e9\u00a0$NCF=10$, pois, contendo a caixa 10 chocolates de leite, h\u00e1 dez maneiras distintas de obter um desses chocolates.<br \/>\nLogo, $P(L)=\\frac{10}{40}=\\frac{1}{4}$.<br \/>\n\u00ad<\/li>\n<li>Relativamente ao acontecimento B: &#8220;ser chocolate branco&#8221;, o n\u00famero de casos favor\u00e1veis \u00e9\u00a0$NCF=9$, pois, contendo a caixa 9 chocolates brancos, h\u00e1 nove maneiras distintas de obter um desses chocolates.<br \/>\nLogo, $P(B)=\\frac{9}{40}$.<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_6937' onClick='GTTabs_show(0,6937)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Uma caixa cont\u00e9m 40 chocolates com a mesma forma e tamanho: 6 s\u00e3o de chocolate com avel\u00e3, 15 de chocolate preto, 10 de chocolate de leite e os restantes de chocolate&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":20339,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,214],"tags":[426,217,216,215],"series":[],"class_list":["post-6937","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-estatistica-e-probabilidades","tag-9-o-ano","tag-acontecimento","tag-espaco-de-resultados","tag-probabilidade"],"views":3525,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/09\/9V1Pag022-15_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6937","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6937"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6937\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20339"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6937"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6937"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6937"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6937"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}