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{"id":6892,"date":"2011-05-25T00:56:10","date_gmt":"2011-05-24T23:56:10","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=6892"},"modified":"2022-01-18T19:33:37","modified_gmt":"2022-01-18T19:33:37","slug":"calcula","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=6892","title":{"rendered":"Calcula"},"content":{"rendered":"<p><ul id='GTTabs_ul_6892' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_6892' class='GTTabs_curr'><a  id=\"6892_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_6892' ><a  id=\"6892_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_6892'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Calcula:<\/p>\n<ol>\n<li>${{(2x-3)}^{2}}$<\/li>\n<li>${{(x+7)}^{2}}$<\/li>\n<li>${{\\left( y+\\frac{1}{2} \\right)}^{2}}$<\/li>\n<li>${{(4a-3b)}^{2}}$<\/li>\n<li>${{(-x-1)}^{2}}$<\/li>\n<li>${{(x+1)}^{2}}$<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_6892' onClick='GTTabs_show(1,6892)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_6892'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{(2x-3)}^{2}} &amp; = &amp; {{(2x)}^{2}}+2\\times 2x\\times (-3)+{{(-3)}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; 4{{x}^{2}}-12x+9\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{(x+7)}^{2}} &amp; = &amp; {{x}^{2}}+2\\times x\\times 7+{{7}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{x}^{2}}+14x+49\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{\\left( y+\\frac{1}{2} \\right)}^{2}} &amp; = &amp; {{y}^{2}}+2\\times y\\times \\frac{1}{2}+{{(\\frac{1}{2})}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{y}^{2}}+y+\\frac{1}{4}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{(4a-3b)}^{2}} &amp; = &amp; {{(4a)}^{2}}+2\\times 4a\\times (-3b)+{{(-3b)}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; 16{{a}^{2}}-24ab+9{{b}^{2}}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{(-x-1)}^{2}} &amp; = &amp; {{(-x)}^{2}}+2\\times (-x)\\times (-1)+{{(-1)}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{x}^{2}}+2x+1\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n{{(x+1)}^{2}} &amp; = &amp; {{x}^{2}}+2\\times x\\times 1+{{1}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{x}^{2}}+2x+1\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_6892' onClick='GTTabs_show(0,6892)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Calcula: ${{(2x-3)}^{2}}$ ${{(x+7)}^{2}}$ ${{\\left( y+\\frac{1}{2} \\right)}^{2}}$ ${{(4a-3b)}^{2}}$ ${{(-x-1)}^{2}}$ ${{(x+1)}^{2}}$ Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":20601,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,193],"tags":[196],"series":[],"class_list":["post-6892","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-de-grau-superior-ao-1-","tag-casos-notaveis"],"views":1662,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/8V2Pag070-15-b_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6892","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6892"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6892\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20601"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6892"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6892"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6892"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6892"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}