{"id":6879,"date":"2011-05-22T21:03:33","date_gmt":"2011-05-22T20:03:33","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=6879"},"modified":"2022-01-19T22:54:46","modified_gmt":"2022-01-19T22:54:46","slug":"calcula-e-simplifica-2","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=6879","title":{"rendered":"Calcula e simplifica"},"content":{"rendered":"<p><ul id='GTTabs_ul_6879' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_6879' class='GTTabs_curr'><a  id=\"6879_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_6879' ><a  id=\"6879_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_6879'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Calcula e simplifica:<\/p>\n<ol>\n<li>$2x({{x}^{2}}+3x-\\frac{1}{2})$<\/li>\n<li>$-3x(-x+4)$<\/li>\n<li>$({{x}^{2}}-7x)\\times \\frac{{{x}^{3}}}{2}$<\/li>\n<li>$(n-2)(n+3)$<\/li>\n<li>$(3a-1)({{a}^{2}}+\\frac{1}{4})$<\/li>\n<li>$(1-m-{{m}^{2}})(m+2)$<\/li>\n<li>$(\\frac{a}{2}-3)({{a}^{2}}-6a)$<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_6879' onClick='GTTabs_show(1,6879)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_6879'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n2x({{x}^{2}}+3x-\\frac{1}{2}) &amp; = &amp; 2x\\times {{x}^{2}}+2x\\times 3x+2x\\times (-\\frac{1}{2})\u00a0 \\\\<br \/>\n{} &amp; = &amp; 2{{x}^{3}}+6{{x}^{2}}-x\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n-3x(-x+4) &amp; = &amp; -3x\\times (-x)-3x\\times 4\u00a0 \\\\<br \/>\n{} &amp; = &amp; 3{{x}^{2}}-12x\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n({{x}^{2}}-7x)\\times \\frac{{{x}^{3}}}{2} &amp; = &amp; {{x}^{2}}\\times \\frac{{{x}^{3}}}{2}-7x\\times \\frac{{{x}^{3}}}{2}\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\frac{{{x}^{5}}}{2}-\\frac{7{{x}^{4}}}{2}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n(n-2)(n+3) &amp; = &amp; n\\times n+n\\times 3-2\\times n-2\\times 3\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{n}^{2}}+3n-2n-6\u00a0 \\\\<br \/>\n{} &amp; = &amp; {{n}^{2}}+n-6\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n(3a-1)({{a}^{2}}+\\frac{1}{4}) &amp; = &amp; 3a\\times {{a}^{2}}+3a\\times \\frac{1}{4}-1\\times {{a}^{2}}-1\\times \\frac{1}{4}\u00a0 \\\\<br \/>\n{} &amp; = &amp; 3{{a}^{3}}+\\frac{3}{4}a-{{a}^{2}}-\\frac{1}{4}\u00a0 \\\\<br \/>\n{} &amp; = &amp; 3{{a}^{3}}-{{a}^{2}}+\\frac{3}{4}a-\\frac{1}{4}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n(1-m-{{m}^{2}})(m+2) &amp; = &amp; 1\\times m+1\\times 2-m\\times m-m\\times 2-{{m}^{2}}\\times m-{{m}^{2}}\\times 2\u00a0 \\\\<br \/>\n{} &amp; = &amp; m+2-{{m}^{2}}-2m-{{m}^{3}}-2{{m}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; -{{m}^{3}}-3{{m}^{2}}-m+2\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n(\\frac{a}{2}-3)({{a}^{2}}-6a) &amp; = &amp; \\frac{a}{2}\\times {{a}^{2}}+\\frac{a}{2}\\times (-6a)-3\\times {{a}^{2}}-3\\times (-6a)\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\frac{{{a}^{3}}}{2}-3{{a}^{2}}-3{{a}^{2}}+18a\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\frac{{{a}^{3}}}{2}-6{{a}^{2}}+18a\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<\/ol>\n<p><strong>Nota<\/strong>: Com a pr\u00e1tica, a primeira passagem, em cada uma das al\u00edneas, tender\u00e1 a ser omitida.<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_6879' onClick='GTTabs_show(0,6879)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Calcula e simplifica: $2x({{x}^{2}}+3x-\\frac{1}{2})$ $-3x(-x+4)$ $({{x}^{2}}-7x)\\times \\frac{{{x}^{3}}}{2}$ $(n-2)(n+3)$ $(3a-1)({{a}^{2}}+\\frac{1}{4})$ $(1-m-{{m}^{2}})(m+2)$ $(\\frac{a}{2}-3)({{a}^{2}}-6a)$ Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":19173,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,193],"tags":[],"series":[],"class_list":["post-6879","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-de-grau-superior-ao-1-"],"views":2102,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat64.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6879","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6879"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6879\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6879"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6879"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6879"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6879"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}