{"id":6868,"date":"2011-05-19T01:23:13","date_gmt":"2011-05-19T00:23:13","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=6868"},"modified":"2022-01-18T02:48:34","modified_gmt":"2022-01-18T02:48:34","slug":"num-circuito-electrico","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=6868","title":{"rendered":"Num circuito el\u00e9trico"},"content":{"rendered":"<p><ul id='GTTabs_ul_6868' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_6868' class='GTTabs_curr'><a  id=\"6868_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_6868' ><a  id=\"6868_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_6868'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"6869\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=6869\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\" data-orig-size=\"120,99\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;}\" data-image-title=\"Circuito el\u00e9ctrico\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\" class=\"alignright wp-image-6869 size-full\" title=\"Circuito el\u00e9ctrico\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\" alt=\"\" width=\"120\" height=\"99\" \/><\/a>Num circuito el\u00e9trico, a diferen\u00e7a de potencial (V) entre dois pontos est\u00e1 relacionada com a intensidade da corrente que o percorre (I) e com a resist\u00eancia do circuito (R), segundo a f\u00f3rmula $V=RI$.<\/p>\n<p>Resolve esta equa\u00e7\u00e3o:<\/p>\n<ol>\n<li>em ordem a R;<\/li>\n<li>em ordem a I.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_6868' onClick='GTTabs_show(1,6868)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_6868'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"6869\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=6869\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\" data-orig-size=\"120,99\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;}\" data-image-title=\"Circuito el\u00e9ctrico\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\" class=\"alignright wp-image-6869 size-full\" title=\"Circuito el\u00e9ctrico\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/Ohmslawvoltagesource.png\" alt=\"\" width=\"120\" height=\"99\" \/><\/a>Resolvendo a equa\u00e7\u00e3o em ordem a R, vem: \\[\\begin{array}{*{35}{l}}<br \/>\nV=RI &amp; \\Leftrightarrow\u00a0 &amp; RI=V\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; \\frac{RI}{I}=\\frac{V}{I}\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; R=\\frac{V}{I}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Resolvendo a equa\u00e7\u00e3o em ordem a I, vem: \\[\\begin{array}{*{35}{l}}<br \/>\nV=RI &amp; \\Leftrightarrow\u00a0 &amp; RI=V\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; \\frac{RI}{R}=\\frac{V}{R}\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; I=\\frac{V}{R}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_6868' onClick='GTTabs_show(0,6868)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Num circuito el\u00e9trico, a diferen\u00e7a de potencial (V) entre dois pontos est\u00e1 relacionada com a intensidade da corrente que o percorre (I) e com a resist\u00eancia do circuito (R), segundo a&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":20593,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,159],"tags":[192],"series":[],"class_list":["post-6868","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-do-1--grau","tag-equacoes-literais"],"views":2278,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2011\/05\/8V2Pag061-5_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6868","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6868"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6868\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20593"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6868"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6868"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6868"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6868"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}