{"id":6771,"date":"2011-04-13T23:07:37","date_gmt":"2011-04-13T22:07:37","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=6771"},"modified":"2022-01-05T16:25:18","modified_gmt":"2022-01-05T16:25:18","slug":"resolve-as-equacoes","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=6771","title":{"rendered":"Resolve as equa\u00e7\u00f5es"},"content":{"rendered":"<p><ul id='GTTabs_ul_6771' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_6771' class='GTTabs_curr'><a  id=\"6771_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_6771' ><a  id=\"6771_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_6771'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Resolve as equa\u00e7\u00f5es:<\/p>\n<ol>\n<li>$\\frac{y}{2}-\\frac{2y+1}{3}=0$<\/li>\n<li>$b-(2b-4)=\\frac{b}{5}$<\/li>\n<li>$\\frac{5(x+2)}{2}-\\frac{x}{5}=5$<\/li>\n<li>$\\frac{4d-3}{8}-\\frac{d}{2}=0$<\/li>\n<li>$\\frac{m+3}{6}-\\frac{2(m-1)}{3}=\\frac{1}{9}$<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_6771' onClick='GTTabs_show(1,6771)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_6771'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n\\frac{y}{\\underset{(3)}{\\mathop{2}}\\,}-\\frac{2y+1}{\\underset{(2)}{\\mathop{3}}\\,}=\\underset{(6)}{\\mathop{0}}\\, &amp; \\Leftrightarrow\u00a0 &amp; 3y-4y-2=0\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; -y=2\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; y=-2\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\nb-(2b-4)=\\frac{b}{5} &amp; \\Leftrightarrow\u00a0 &amp; \\underset{(5)}{\\mathop{b}}\\,-\\underset{(5)}{\\mathop{2b}}\\,+\\underset{(5)}{\\mathop{4}}\\,=\\frac{b}{\\underset{(1)}{\\mathop{5}}\\,}\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 5b-10b+20=b\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; -6b=-20\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; b=\\frac{20}{6}\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; b=\\frac{10}{3}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n\\frac{5(x+2)}{2}-\\frac{x}{5}=5 &amp; \\Leftrightarrow\u00a0 &amp; \\frac{5x+10}{\\underset{(5)}{\\mathop{2}}\\,}-\\frac{x}{\\underset{(2)}{\\mathop{5}}\\,}=\\underset{(10)}{\\mathop{5}}\\,\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 25x+50-2x=50\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 23x=0\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; x=0\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n\\frac{4d-3}{\\underset{(1)}{\\mathop{8}}\\,}-\\frac{d}{\\underset{(4)}{\\mathop{2}}\\,}=\\underset{(8)}{\\mathop{0}}\\, &amp; \\Leftrightarrow\u00a0 &amp; 4d-3-4d=0\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 0d=3\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\nA equa\u00e7\u00e3o \u00e9 imposs\u00edvel.<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n\\frac{m+3}{6}-\\frac{2(m-1)}{3}=\\frac{1}{9} &amp; \\Leftrightarrow\u00a0 &amp; \\frac{m+3}{\\underset{(3)}{\\mathop{6}}\\,}-\\frac{2m-2}{\\underset{(6)}{\\mathop{3}}\\,}=\\frac{1}{\\underset{(2)}{\\mathop{9}}\\,}\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 3m+9-12m+12=2\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; -9m=-19\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; m=\\frac{19}{9}\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_6771' onClick='GTTabs_show(0,6771)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Resolve as equa\u00e7\u00f5es: $\\frac{y}{2}-\\frac{2y+1}{3}=0$ $b-(2b-4)=\\frac{b}{5}$ $\\frac{5(x+2)}{2}-\\frac{x}{5}=5$ $\\frac{4d-3}{8}-\\frac{d}{2}=0$ $\\frac{m+3}{6}-\\frac{2(m-1)}{3}=\\frac{1}{9}$ Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":14061,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,159],"tags":[425],"series":[],"class_list":["post-6771","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-do-1--grau","tag-equacoes"],"views":2524,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/Mat06.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6771","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6771"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6771\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6771"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6771"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6771"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6771"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}