{"id":6688,"date":"2011-04-04T22:39:05","date_gmt":"2011-04-04T21:39:05","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=6688"},"modified":"2022-01-05T22:43:18","modified_gmt":"2022-01-05T22:43:18","slug":"os-comprimentos-dos-lados-de-um-triangulo","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=6688","title":{"rendered":"Os comprimentos dos lados de um tri\u00e2ngulo"},"content":{"rendered":"<p><ul id='GTTabs_ul_6688' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_6688' class='GTTabs_curr'><a  id=\"6688_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_6688' ><a  id=\"6688_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_6688'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Os comprimentos dos lados de um tri\u00e2ngulo [MNO] s\u00e3o 6 cm, 7 cm e 10 cm.<\/p>\n<p>Determina os comprimentos dos lados de um tri\u00e2ngulo semelhante a [MNO]:<\/p>\n<ol>\n<li>cujo lado maior \u00e9 12 cm.<\/li>\n<li>cujo lado menor \u00e9 12 cm.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_6688' onClick='GTTabs_show(1,6688)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_6688'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Calculemos o lado interm\u00e9dio:<br \/>\n\\[\\frac{12}{10}=\\frac{x}{7}\\Leftrightarrow x=\\frac{12\\times 7}{10}\\Leftrightarrow x=8,4\\]<br \/>\nCalculemos o menor lado:<br \/>\n\\[\\frac{12}{10}=\\frac{y}{6}\\Leftrightarrow y=\\frac{12\\times 6}{10}\\Leftrightarrow y=7,2\\]<br \/>\nPortanto, os lados desses tri\u00e2ngulo t\u00eam de comprimento 7,2 cm, 8,4 cm e 12 cm.<br \/>\n\u00ad<\/li>\n<li>Calculemos o lado interm\u00e9dio:<br \/>\n\\[\\frac{12}{6}=\\frac{x}{7}\\Leftrightarrow x=\\frac{12\\times 7}{6}\\Leftrightarrow x=14\\]<br \/>\nCalculemos o maior lado:<br \/>\n\\[\\frac{12}{6}=\\frac{y}{10}\\Leftrightarrow y=\\frac{12\\times 10}{6}\\Leftrightarrow y=20\\]<br \/>\nPortanto, os lados desses tri\u00e2ngulo t\u00eam de comprimento\u00a012 cm,\u00a014 cm e 20 cm.<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_6688' onClick='GTTabs_show(0,6688)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Os comprimentos dos lados de um tri\u00e2ngulo [MNO] s\u00e3o 6 cm, 7 cm e 10 cm. Determina os comprimentos dos lados de um tri\u00e2ngulo semelhante a [MNO]: cujo lado maior \u00e9&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":14065,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,151],"tags":[149],"series":[],"class_list":["post-6688","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-semelhanca-de-triangulos-8--ano","tag-semelhanca-de-triangulos"],"views":2372,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/Mat10.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6688","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6688"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6688\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/14065"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6688"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6688"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6688"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6688"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}