\nEnunciado<\/b><\/span><\/p>\n
$\"\"$ <\/a>Um copo tem interiormente a forma de um cone de revolu\u00e7\u00e3o.<\/p>\n
Tendo em conta as indica\u00e7\u00f5es da figura, calcula:<\/p>\n
\n
a altura do copo;<\/li>\n
um valor aproximado \u00e0s unidades da capacidade do copo.<\/li>\n<\/ol>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
\n
$\"\"$ <\/a>Aplicando o teorema de Pit\u00e1goras, determinemos a altura do cone:\n
$$\\begin{array}{*{35}{l}}
\n{{h}^{2}}={{10}^{2}}-{{6}^{2}} & \\Leftrightarrow\u00a0 & {{h}^{2}}=100-36\u00a0 \\\\
\n{} & \\Leftrightarrow\u00a0 & {{h}^{2}}=64\u00a0 \\\\
\n{} & Logo, & h=8\u00a0 \\\\
\n\\end{array}$$<\/p>\n
Portanto, o copo tem 18 cm de altura ($8+10$).<\/p>\n<\/li>\n
O volume do cone \u00e9:\n
$$V=\\frac{1}{3}\\times (\\pi \\times {{6}^{2}})\\times 8=\\frac{36\\pi \\times 8}{3}=12\\pi \\times 8=96\\pi \\simeq 302\\,c{{m}^{3}}$$<\/p>\n
O copo tem, aproximadamente, $302\\,c{{m}^{3}}$ de capacidade.<\/p>\n<\/li>\n<\/ol>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Um copo tem interiormente a forma de um cone de revolu\u00e7\u00e3o. Tendo em conta as indica\u00e7\u00f5es da figura, calcula: a altura do copo; um valor aproximado \u00e0s unidades da capacidade do...<\/p>\n","protected":false},"author":1,"featured_media":20685,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,112],"tags":[424,67,118],"series":[],"class_list":["post-6427","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-decomposicao-de-figuras-teorema-de-pitagoras","tag-8-o-ano","tag-geometria","tag-teorema-de-pitagoras"],"views":1981,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/12\/8V1Pag039-6-b_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6427","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=6427"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/6427\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20685"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=6427"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=6427"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=6427"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=6427"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}