{"id":5793,"date":"2010-11-20T00:07:38","date_gmt":"2010-11-20T00:07:38","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=5793"},"modified":"2022-01-14T22:01:31","modified_gmt":"2022-01-14T22:01:31","slug":"rascunho-33","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=5793","title":{"rendered":"Decomposi\u00e7\u00e3o de um tri\u00e2ngulo por uma mediana"},"content":{"rendered":"<p style=\"text-align: center;\"><script src=\"https:\/\/cdn.geogebra.org\/apps\/deployggb.js\"><\/script>\r\n<div id=\"ggbApplet\" style=\"margin: 0 auto;\"><\/div>\r\n<script>\r\nvar parameters = {\r\n\"id\": \"ggbApplet\",\r\n\"width\":832,\r\n\"height\":443,\r\n\"showMenuBar\":false,\r\n\"showAlgebraInput\":false,\r\n\"showToolBar\":false,\r\n\"customToolBar\":\"0 39 | 1 501 67 , 5 19 , 72 | 2 15 45 , 18 65 , 7 37 | 4 3 8 9 , 13 44 , 58 , 47 | 16 51 64 , 70 | 10 34 53 11 , 24  20 22 , 21 23 | 55 56 57 , 12 | 36 46 , 38 49  50 , 71 | 30 29 54 32 31 33 | 17 26 62 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is3D=is 3D applet using 3D view, AV=Algebra View, SV=Spreadsheet View, CV=CAS View, EV2=Graphics View 2, CP=Construction Protocol, PC=Probability Calculator, DA=Data Analysis, FI=Function Inspector, PV=Python, macro=Macro View\r\nvar views = {'is3D': 0,'AV': 0,'SV': 0,'CV': 0,'EV2': 0,'CP': 1,'PC': 0,'DA': 0,'FI': 0,'PV': 0,'macro': 0};\r\nvar applet = new GGBApplet(parameters, '5.0', views);\r\nwindow.onload = function() {applet.inject('ggbApplet')};\r\n<\/script><\/p>\n<p>1- Considera o tri\u00e2ngulo [ABC].<\/p>\n<p>2 &#8211; Desenha a mediana relativa ao lado [BC], ativando a caixa &#8220;Mostrar mediana relativa a [AC]&#8221;.<\/p>\n<blockquote>\n<p><strong>Mediana de um tri\u00e2ngulo<\/strong> \u00e9 o segmento de reta que une um v\u00e9rtice ao ponto m\u00e9dio do lado oposto a esse v\u00e9rtice.<\/p>\n<\/blockquote>\n<p>3 &#8211; Considera os tri\u00e2ngulos [ABD] e [BCD], ativando as caixas correspondentes.<\/p>\n<p>4 &#8211; Altera a configura\u00e7\u00e3o do tri\u00e2ngulo [ABC] e tenta encontrar uma justifica\u00e7\u00e3o para a rela\u00e7\u00e3o entre os valores das \u00e1reas encontradas.<\/p>\n<p>5 &#8211; Caso n\u00e3o encontres uma explica\u00e7\u00e3o, ativa a caixa &#8220;Mostrar altura&#8221;. Qual \u00e9 a justifica\u00e7\u00e3o para a rela\u00e7\u00e3o das \u00e1reas dos tri\u00e2ngulos?<\/p>\n<p>6 &#8211; Desenha as outras medianas do tri\u00e2ngulo, assim como o baricentro do tri\u00e2ngulo [ABC], ativando as caixas respetivas. Altera a configura\u00e7\u00e3o do tri\u00e2ngulo [ABC].<\/p>\n<blockquote>\n<p><strong>Baricentro de um tri\u00e2ngulo<\/strong> \u00e9 o ponto de intersec\u00e7\u00e3o das medianas.<\/p>\n<\/blockquote>\n<p><strong><br \/>\nSabias que&#8230;<br \/>\n<\/strong>Se desejares, podes conhecer outros pontos not\u00e1veis do tri\u00e2ngulo, explorando a atividade <a href=\"https:\/\/www.acasinhadamatematica.pt\/?page_id=27\">A linha de Euler<\/a>\u00a0do 8.\u00ba ano.<\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Explora\u00e7\u00e3o din\u00e2mica da representa\u00e7\u00e3o das medianas e do baricentro de um tri\u00e2ngulo, bem como a interpreta\u00e7\u00e3o das suas propriedades.<\/p>\n","protected":false},"author":1,"featured_media":19234,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,112],"tags":[424,67,115],"series":[],"class_list":["post-5793","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-decomposicao-de-figuras-teorema-de-pitagoras","tag-8-o-ano","tag-geometria","tag-mediana"],"views":4455,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat76.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/5793","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=5793"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/5793\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19234"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=5793"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=5793"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=5793"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=5793"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}