{"id":5682,"date":"2010-11-19T01:23:15","date_gmt":"2010-11-19T01:23:15","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=5682"},"modified":"2022-01-19T17:48:13","modified_gmt":"2022-01-19T17:48:13","slug":"calcula-a-area-do-trapezio","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=5682","title":{"rendered":"Calcula a \u00e1rea do trap\u00e9zio"},"content":{"rendered":"<p><ul id='GTTabs_ul_5682' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_5682' class='GTTabs_curr'><a  id=\"5682_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_5682' ><a  id=\"5682_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_5682'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"5683\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=5683\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg\" data-orig-size=\"447,297\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;HP pstc4380&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;}\" data-image-title=\"Trap\u00e9zio\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg\" class=\"alignright wp-image-5683\" title=\"Trap\u00e9zio\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-300x199.jpg\" alt=\"\" width=\"300\" height=\"199\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-300x199.jpg 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-150x99.jpg 150w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-400x265.jpg 400w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg 447w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a>Calcula a \u00e1rea do trap\u00e9zio:<\/p>\n<ol>\n<li>decompondo-o em dois tri\u00e2ngulos e um quadrado;<\/li>\n<li>usando a f\u00f3rmula para determinar a \u00e1rea de um trap\u00e9zio.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_5682' onClick='GTTabs_show(1,5682)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_5682'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"5683\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=5683\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg\" data-orig-size=\"447,297\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;HP pstc4380&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;}\" data-image-title=\"Trap\u00e9zio\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg\" class=\"alignright wp-image-5683\" title=\"Trap\u00e9zio\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-300x199.jpg\" alt=\"\" width=\"300\" height=\"199\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-300x199.jpg 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-150x99.jpg 150w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6-400x265.jpg 400w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/pag24-6.jpg 447w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a>Decompondo o trap\u00e9zio em dois tri\u00e2ngulos e um quadrado, temos:\n<p>$$\\begin{array}{*{35}{l}}<br \/>\n{{A}_{Trap\\acute{e}zio}} &amp; = &amp; 2\\times {{A}_{Tri\\hat{a}ngulo}}+{{A}_{Quadrado}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; 2\\times \\frac{1,4\\times 2,8}{2}+{{(2,8)}^{2}}\u00a0 \\\\<br \/>\n{} &amp; = &amp; 3,92+7,84\u00a0 \\\\<br \/>\n{} &amp; = &amp; 11,76\\,\\,d{{m}^{2}}\u00a0 \\\\<br \/>\n\\end{array}$$<br \/>\n\u00ad<\/p>\n<\/li>\n<li>Usando a f\u00f3rmula para determinar a \u00e1rea de um trap\u00e9zio, temos:\n<p>$$\\begin{array}{*{35}{l}}<br \/>\n{{A}_{Trap\\acute{e}zio}} &amp; = &amp; \\frac{(1,4+2,8+1,4)+2,8}{2}\\times 2,8\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\frac{5,6+2,8}{2}\\times 2,8\u00a0 \\\\<br \/>\n{} &amp; = &amp; 4,2\\times 2,8\u00a0 \\\\<br \/>\n{} &amp; = &amp; 11,76\\,\\,d{{m}^{2}}\u00a0 \\\\<br \/>\n\\end{array}$$<\/p>\n<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_5682' onClick='GTTabs_show(0,5682)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Calcula a \u00e1rea do trap\u00e9zio: decompondo-o em dois tri\u00e2ngulos e um quadrado; usando a f\u00f3rmula para determinar a \u00e1rea de um trap\u00e9zio. Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":20656,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,112],"tags":[424,108,67,113],"series":[],"class_list":["post-5682","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-decomposicao-de-figuras-teorema-de-pitagoras","tag-8-o-ano","tag-area","tag-geometria","tag-trapezio"],"views":5795,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/11\/8V1Pag024-6_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/5682","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=5682"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/5682\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20656"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=5682"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=5682"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=5682"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=5682"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}