{"id":4306,"date":"2010-10-19T01:53:57","date_gmt":"2010-10-19T00:53:57","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=4306"},"modified":"2022-01-13T16:23:09","modified_gmt":"2022-01-13T16:23:09","slug":"exprima-ax-em-funcao-de-senx-e-cos-x","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=4306","title":{"rendered":"Exprima A(x) em fun\u00e7\u00e3o de senx e cos x"},"content":{"rendered":"<p><ul id='GTTabs_ul_4306' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_4306' class='GTTabs_curr'><a  id=\"4306_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_4306' ><a  id=\"4306_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_4306'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Exprima A(x) em fun\u00e7\u00e3o de sen x e cos x.<\/p>\n<ol>\n<li>$A(x)=sen\\,(-x)-sen\\,(\\pi -x)$<\/li>\n<li>$A(x)=\\cos (-x)+\\cos (\\pi +x)$<\/li>\n<li>$A(x)=sen\\,(\\frac{\\pi }{2}-x)+\\cos (\\frac{5\\pi }{2}-x)$<\/li>\n<li>$A(x)=\\cos (\\frac{3\\pi }{2}+x)+sen\\,(x-\\frac{5\\pi }{2})$<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_4306' onClick='GTTabs_show(1,4306)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_4306'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\nA(x) &amp; = &amp; sen\\,(-x)-sen\\,(\\pi -x)\u00a0 \\\\<br \/>\n{} &amp; = &amp; -sen\\,x-sen\\,x\u00a0 \\\\<br \/>\n{} &amp; = &amp; -2sen\\,x\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\nA(x) &amp; = &amp; \\cos (-x)+\\cos (\\pi +x)\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\cos x-\\cos x\u00a0 \\\\<br \/>\n{} &amp; = &amp; 0\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\nA(x) &amp; = &amp; sen\\,(\\frac{\\pi }{2}-x)+\\cos (\\frac{5\\pi }{2}-x)\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\cos x+\\cos (\\frac{\\pi }{2}-x)\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\cos x+sen\\,x\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<li>Ora,<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\nA(x) &amp; = &amp; \\cos (\\frac{3\\pi }{2}+x)+sen\\,(x-\\frac{5\\pi }{2})\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\cos (2\\pi -\\frac{\\pi }{2}+x)+sen\\,(x-\\frac{\\pi }{2})\u00a0 \\\\<br \/>\n{} &amp; = &amp; \\cos (\\frac{\\pi }{2}-x)-sen\\,(\\frac{\\pi }{2}-x)\u00a0 \\\\<br \/>\n{} &amp; = &amp; sen\\,x-\\cos x\u00a0 \\\\<br \/>\n\\end{array}\\]<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_4306' onClick='GTTabs_show(0,4306)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Exprima A(x) em fun\u00e7\u00e3o de sen x e cos x. $A(x)=sen\\,(-x)-sen\\,(\\pi -x)$ $A(x)=\\cos (-x)+\\cos (\\pi +x)$ $A(x)=sen\\,(\\frac{\\pi }{2}-x)+\\cos (\\frac{5\\pi }{2}-x)$ $A(x)=\\cos (\\frac{3\\pi }{2}+x)+sen\\,(x-\\frac{5\\pi }{2})$ Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":14083,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[98,97,99],"tags":[422,423],"series":[],"class_list":["post-4306","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-11--ano","category-aplicando","category-trigonometria","tag-11-o-ano","tag-trigonometria"],"views":2539,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/Mat28.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/4306","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=4306"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/4306\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/14083"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=4306"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=4306"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=4306"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=4306"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}