{"id":3476,"date":"2010-10-03T18:38:02","date_gmt":"2010-10-03T17:38:02","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=3476"},"modified":"2022-01-05T13:15:57","modified_gmt":"2022-01-05T13:15:57","slug":"quatro-equacoes","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=3476","title":{"rendered":"Quatro equa\u00e7\u00f5es"},"content":{"rendered":"<p><ul id='GTTabs_ul_3476' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_3476' class='GTTabs_curr'><a  id=\"3476_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_3476' ><a  id=\"3476_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_3476'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Resolve e classifica cada uma das equa\u00e7\u00f5es:<\/p>\n<ol>\n<li>$7x-3=7x$<\/li>\n<li>$8x+1=2x+1$<\/li>\n<li>$-2x+3=-2x+3$<\/li>\n<li>$5x+2=5(x-2)$<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_3476' onClick='GTTabs_show(1,3476)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_3476'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Resolvendo a equa\u00e7\u00e3o, temos:<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n7x-3=7x &amp; \\Leftrightarrow\u00a0 &amp; 7x-7x=3\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 0x=3\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\nComo sabemos, o produto de qualquer n\u00famero por zero \u00e9 nulo.<br \/>\nLogo, a equa\u00e7\u00e3o \u00e9 imposs\u00edvel. O seu conjunto-solu\u00e7\u00e3o \u00e9 vazio: $S=\\left\\{ {} \\right\\}$.<br \/>\n\u00ad<\/li>\n<li>Resolvendo a equa\u00e7\u00e3o, temos:<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n8x+1=2x+1 &amp; \\Leftrightarrow\u00a0 &amp; 8x-2x=1-1\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 6x=0\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; \\frac{6x}{6}=\\frac{0}{6}\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; x=0\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\nA equa\u00e7\u00e3o \u00e9 poss\u00edvel. O seu conjunto-solu\u00e7\u00e3o \u00e9 $S=\\left\\{ 0 \\right\\}$.<br \/>\n\u00ad<\/li>\n<li>Resolvendo a equa\u00e7\u00e3o, temos:<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n-2x+3=-2x+3 &amp; \\Leftrightarrow\u00a0 &amp; -2x+2x=3-3\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 0x=0\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\nComo sabemos, o produto de qualquer n\u00famero por zero \u00e9 nulo.<br \/>\nLogo, a equa\u00e7\u00e3o \u00e9 poss\u00edvel indeterminada.<br \/>\n\u00ad<\/li>\n<li>Resolvendo a equa\u00e7\u00e3o, temos:<br \/>\n\\[\\begin{array}{*{35}{l}}<br \/>\n5x+2=5(x-2) &amp; \\Leftrightarrow\u00a0 &amp; 5x+2=5x-10\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 0x=-12\u00a0 \\\\<br \/>\n\\end{array}\\]<br \/>\nComo sabemos, o produto de qualquer n\u00famero por zero \u00e9 nulo.<br \/>\nLogo, a equa\u00e7\u00e3o \u00e9 imposs\u00edvel. O seu conjunto-solu\u00e7\u00e3o \u00e9 vazio: $S=\\left\\{ {} \\right\\}$.<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_3476' onClick='GTTabs_show(0,3476)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Resolve e classifica cada uma das equa\u00e7\u00f5es: $7x-3=7x$ $8x+1=2x+1$ $-2x+3=-2x+3$ $5x+2=5(x-2)$ Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":19189,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,101],"tags":[424,425],"series":[],"class_list":["post-3476","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes","tag-8-o-ano","tag-equacoes"],"views":1923,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat75.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/3476","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=3476"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/3476\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19189"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=3476"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=3476"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=3476"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=3476"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}