{"id":3326,"date":"2010-10-01T01:20:35","date_gmt":"2010-10-01T00:20:35","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=3326"},"modified":"2022-01-18T21:44:28","modified_gmt":"2022-01-18T21:44:28","slug":"a-ana-e-a-maria","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=3326","title":{"rendered":"A Ana e a Maria"},"content":{"rendered":"<p><ul id='GTTabs_ul_3326' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_3326' class='GTTabs_curr'><a  id=\"3326_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_3326' ><a  id=\"3326_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<li id='GTTabs_li_2_3326' ><a  id=\"3326_2\" onMouseOver=\"GTTabsShowLinks('Extens\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Extens\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_3326'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/10\/bonecas.jpg\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"3519\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=3519\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/10\/bonecas.jpg\" data-orig-size=\"400,367\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;}\" data-image-title=\"Bonecas\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/10\/bonecas.jpg\" class=\"alignright size-thumbnail wp-image-3519\" title=\"Bonecas\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/10\/bonecas-150x150.jpg\" alt=\"\" width=\"150\" height=\"150\" \/><\/a>A Ana e a Maria s\u00e3o irm\u00e3s e a soma das suas idades \u00e9 igual a 35.<\/p>\n<p>Qual \u00e9 a idade da Ana, se a Maria \u00e9 cinco anos mais nova?<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_3326' onClick='GTTabs_show(1,3326)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_3326'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<p>Designando por <em><strong>a<\/strong><\/em> a idade da Ana, temos:<\/p>\n<ul>\n<li>Idade da Ana: $a$<\/li>\n<li>Idade da Maria: $a-5$<\/li>\n<\/ul>\n<p>Logo, o problema pode ser equacionado por: \\[a+(a-5)=35\\]<\/p>\n<p>Resolvendo a equa\u00e7\u00e3o, vem: \\[\\begin{array}{*{35}{l}}<br \/>\na+(a-5)=35 &amp; \\Leftrightarrow\u00a0 &amp; a+a-5=35\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 2a=40\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; a=20\u00a0 \\\\<br \/>\n\\end{array}\\]<\/p>\n<p>Portanto, a Ana tem 20 anos de idade.<\/p>\n<p><span style=\"color: #000080;\">Como resolver o problema, designado por <strong><em>m<\/em><\/strong> a idade da Maria?<\/span><\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_3326' onClick='GTTabs_show(0,3326)'>&lt;&lt; Enunciado<\/a><\/span><span class='GTTabs_nav_next'><a href='#GTTabs_ul_3326' onClick='GTTabs_show(2,3326)'>Extens\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_2_3326'>\n<span class='GTTabs_titles'><b>Extens\u00e3o<\/b><\/span><\/p>\n<p>Designando por <em><strong>m<\/strong><\/em> a idade da Maria, temos:<\/p>\n<ul>\n<li>Idade da Maria: $m$<\/li>\n<li>Idade da Ana: $m+5$<\/li>\n<\/ul>\n<p>Logo, o problema pode ser equacionado por: \\[m+(m+5)=35\\]<\/p>\n<p>Resolvendo a equa\u00e7\u00e3o, vem: \\[\\begin{array}{*{35}{l}}<br \/>\nm+(m+5)=35 &amp; \\Leftrightarrow\u00a0 &amp; m+m+5=35\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; 2m=30\u00a0 \\\\<br \/>\n{} &amp; \\Leftrightarrow\u00a0 &amp; m=15\u00a0 \\\\<br \/>\n\\end{array}\\]<\/p>\n<p>Como a Maria tem 15 anos, ent\u00e3o a Ana tem 20 anos de idade, pois \u00e9 cinco anos mais velha.<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_3326' onClick='GTTabs_show(1,3326)'>&lt;&lt; Resolu\u00e7\u00e3o<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado A Ana e a Maria s\u00e3o irm\u00e3s e a soma das suas idades \u00e9 igual a 35. Qual \u00e9 a idade da Ana, se a Maria \u00e9 cinco anos mais nova?&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":20606,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,101],"tags":[424,425],"series":[],"class_list":["post-3326","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes","tag-8-o-ano","tag-equacoes"],"views":2171,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2010\/10\/7V2Pag066-4_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/3326","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=3326"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/3326\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20606"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=3326"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=3326"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=3326"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=3326"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}