{"id":26236,"date":"2023-06-05T18:49:47","date_gmt":"2023-06-05T17:49:47","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=26236"},"modified":"2023-06-05T19:19:21","modified_gmt":"2023-06-05T18:19:21","slug":"a-solucao-de-outro-sistema-de-equacoes","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=26236","title":{"rendered":"A solu\u00e7\u00e3o de outro sistema de equa\u00e7\u00f5es"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_26236' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_26236' class='GTTabs_curr'><a  id=\"26236_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_26236' ><a  id=\"26236_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_26236'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Considera o seguinte sistema de equa\u00e7\u00f5es.<\/p>\n<p>\\[\\left\\{ {\\begin{array}{*{20}{l}}{x + y = 3}\\\\{2y = \\frac{{x + y}}{3}}\\end{array}} \\right.\\]<\/p>\n<p>Qual \u00e9 o par ordenado (<em>x<\/em>, <em>y<\/em>) que \u00e9 solu\u00e7\u00e3o do sistema?<br \/>Mostra como chegaste \u00e0 tua resposta.<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_26236' onClick='GTTabs_show(1,26236)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_26236'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>Considera o seguinte sistema de equa\u00e7\u00f5es.<\/p>\n<p>\\[\\left\\{ {\\begin{array}{*{20}{l}}{x + y = 3}\\\\{2y = \\frac{{x + y}}{3}}\\end{array}} \\right.\\]<\/p>\n<p>Qual \u00e9 o par ordenado (<em>x<\/em>, <em>y<\/em>) que \u00e9 solu\u00e7\u00e3o do sistema?<br \/>Mostra como chegaste \u00e0 tua resposta.<\/p>\n<\/blockquote>\n<p><br \/>Resolvendo o sistema de equa\u00e7\u00f5es, vem: \\[\\begin{array}{*{20}{l}}{\\left\\{ {\\begin{array}{*{20}{l}}{x + y = 3}\\\\{2y = \\frac{{x + y}}{3}}\\end{array}} \\right.}&amp; \\Leftrightarrow &amp;{\\left\\{ {\\begin{array}{*{20}{l}}{x + y = 3}\\\\{6y = x + y}\\end{array}} \\right.}&amp; \\Leftrightarrow &amp;{\\left\\{ {\\begin{array}{*{20}{l}}{x + y = 3}\\\\{6y = 3}\\end{array}} \\right.}&amp; \\Leftrightarrow &amp;{\\left\\{ {\\begin{array}{*{20}{l}}{y = \\frac{1}{2}}\\\\{x = \\frac{5}{2}}\\end{array}} \\right.}\\end{array}\\]<\/p>\n<p>Portanto, o par ordenado que \u00e9 solu\u00e7\u00e3o do sistema \u00e9 \\(\\left( {\\frac{5}{2},\\frac{1}{2}} \\right)\\).<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_26236' onClick='GTTabs_show(0,26236)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Considera o seguinte sistema de equa\u00e7\u00f5es. \\[\\left\\{ {\\begin{array}{*{20}{l}}{x + y = 3}\\\\{2y = \\frac{{x + y}}{3}}\\end{array}} \\right.\\] Qual \u00e9 o par ordenado (x, y) que \u00e9 solu\u00e7\u00e3o do sistema?Mostra como chegaste&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":19188,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,714],"tags":[424,345,239],"series":[],"class_list":["post-26236","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-literais-e-sistemas","tag-8-o-ano","tag-funcao-afim","tag-sistema-de-equacoes"],"views":67,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat74.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/26236","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=26236"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/26236\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19188"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=26236"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=26236"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=26236"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=26236"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}