{"id":25981,"date":"2023-05-23T20:05:27","date_gmt":"2023-05-23T19:05:27","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=25981"},"modified":"2023-05-23T21:52:52","modified_gmt":"2023-05-23T20:52:52","slug":"a-pressao-sanguinea-normal","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=25981","title":{"rendered":"A press\u00e3o sangu\u00ednea normal"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_25981' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_25981' class='GTTabs_curr'><a  id=\"25981_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_25981' ><a  id=\"25981_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_25981'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>A press\u00e3o sangu\u00ednea normal, <em>P<\/em>, de uma pessoa saud\u00e1vel pode ser estimada mediante a express\u00e3o \\[P = 11 + \\frac{E}{{20}}\\] onde <em>E<\/em> representa a idade em anos.<\/p>\n<ol>\n<li>Estima a press\u00e3o sangu\u00ednea normal estimada aos 30, 50 e 70 anos.<\/li>\n<li>Escreve uma express\u00e3o que te permita estimar a idade, conhecendo a press\u00e3o sangu\u00ednea.<\/li>\n<li>Se uma pessoa tem uma press\u00e3o sangu\u00ednea de 14, qual esperas que seja a sua idade?<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_25981' onClick='GTTabs_show(1,25981)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_25981'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>A press\u00e3o sangu\u00ednea normal, <em>P<\/em>, de uma pessoa saud\u00e1vel pode ser estimada mediante a express\u00e3o \\[P = 11 + \\frac{E}{{20}}\\] onde <em>E<\/em> representa a idade em anos.<\/p>\n<\/blockquote>\n<p>\u00a0<\/p>\n<ol>\n<li>\u00c9 a seguinte, a press\u00e3o sangu\u00ednea normal estimada aos 30, 50 e 70 anos:<br \/>\\(P\\left( {30} \\right) = 11 + \\frac{{30}}{{20}} = 12,5\\)<br \/>\\(P\\left( {50} \\right) = 11 + \\frac{{50}}{{20}} = 13,5\\)<br \/>\\(P\\left( {70} \\right) = 11 + \\frac{{70}}{{20}} = 14,5\\)<br \/><br \/><\/li>\n<li>Uma express\u00e3o que permite estimar a idade, conhecendo a press\u00e3o sangu\u00ednea, \u00e9 \\({E = 20P &#8211; 220}\\), pois \\[\\begin{array}{*{20}{l}}{P = 11 + \\frac{E}{{20}}}&amp; \\Leftrightarrow &amp;{20P = 220 + E}\\\\{}&amp; \\Leftrightarrow &amp;{E = 20P &#8211; 220}\\end{array}\\]<\/li>\n<li>Se uma pessoa tem uma press\u00e3o sangu\u00ednea de 14, espera-se que tenha \\(E\\left( {14} \\right) = 20 \\times 14 &#8211; 220 = 60\\) anos de idade.<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_25981' onClick='GTTabs_show(0,25981)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado A press\u00e3o sangu\u00ednea normal, P, de uma pessoa saud\u00e1vel pode ser estimada mediante a express\u00e3o \\[P = 11 + \\frac{E}{{20}}\\] onde E representa a idade em anos. Estima a press\u00e3o sangu\u00ednea&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":19177,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,714],"tags":[424,192,345],"series":[],"class_list":["post-25981","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-literais-e-sistemas","tag-8-o-ano","tag-equacoes-literais","tag-funcao-afim"],"views":88,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat68.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25981","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=25981"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25981\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19177"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=25981"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=25981"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=25981"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=25981"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}