\nEnunciado<\/b><\/span><\/p>\n
Considera a equa\u00e7\u00e3o: \\(\\frac{3}{2}x + 2y = 3\\)<\/p>\n
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O par \\(\\left( {2, – 1} \\right)\\) \u00e9 solu\u00e7\u00e3o?<\/li>\n
Resolve a equa\u00e7\u00e3o em ordem a y<\/em>.<\/li>\n
Procura o valor de y<\/em> para \\(x = – 4\\).<\/li>\n
Qual \u00e9 o valor de x<\/em> para \\(y = 0\\)?<\/li>\n<\/ol>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
\n
Considera a equa\u00e7\u00e3o: \\[\\frac{3}{2}x + 2y = 3\\]<\/p>\n<\/blockquote>\n
\u00a0<\/p>\n
\n
Na equa\u00e7\u00e3o dada, substituindo x<\/em> por 2 e y<\/em> por \u22121, obtemos uma proposi\u00e7\u00e3o falsa: \\[\\begin{array}{*{20}{c}}{\\frac{3}{2} \\times 2 + 2 \\times \\left( { – 1} \\right) = 3}& \\Leftrightarrow &{1 = 3}\\end{array}\\] Logo, o par \\(\\left( {2, – 1} \\right)\\) n\u00e3o \u00e9 solu\u00e7\u00e3o da equa\u00e7\u00e3o.

<\/li>\n
Resolvendo a equa\u00e7\u00e3o em ordem a y<\/em>, temos:
\\[\\begin{array}{*{20}{l}}{\\frac{3}{2}x + 2y = 3}& \\Leftrightarrow &{3x + 4y = 6}\\\\{}& \\Leftrightarrow &{4y = 6 – 3x}\\\\{}& \\Leftrightarrow &{y = – \\frac{3}{4}x + \\frac{3}{2}}\\end{array}\\]<\/li>\n
Procurando o valor de y<\/em> para \\(x = – 4\\), temos: \\[y = – \\frac{3}{4} \\times \\left( { – 4} \\right) + \\frac{3}{2} = 3 + \\frac{3}{2} = \\frac{9}{2}\\]<\/li>\n
O valor de x<\/em> para \\(y = 0\\) \u00e9:
\\[\\begin{array}{*{20}{l}}{\\frac{3}{2}x + 2 \\times 0 = 3}& \\Leftrightarrow &{3x + 0 = 6}\\\\{}& \\Leftrightarrow &{x = 2}\\end{array}\\]<\/li>\n<\/ol>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Considera a equa\u00e7\u00e3o: \\(\\frac{3}{2}x + 2y = 3\\) O par \\(\\left( {2, – 1} \\right)\\) \u00e9 solu\u00e7\u00e3o? Resolve a equa\u00e7\u00e3o em ordem a y. Procura o valor de y para \\(x...<\/p>\n","protected":false},"author":1,"featured_media":19176,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,714],"tags":[424,192],"series":[],"class_list":["post-25944","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-literais-e-sistemas","tag-8-o-ano","tag-equacoes-literais"],"views":82,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat67.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25944","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=25944"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25944\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19176"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=25944"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=25944"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=25944"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=25944"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}