{"id":25800,"date":"2023-05-20T23:23:35","date_gmt":"2023-05-20T22:23:35","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=25800"},"modified":"2023-05-21T00:41:00","modified_gmt":"2023-05-20T23:41:00","slug":"observa-as-imagens","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=25800","title":{"rendered":"Observa as imagens"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_25800' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_25800' class='GTTabs_curr'><a  id=\"25800_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_25800' ><a  id=\"25800_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_25800'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Observa as imagens e responde \u00e0 quest\u00e3o colocada.<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25805\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25805\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all.png\" data-orig-size=\"790,940\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag198-T9-all\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all.png\" class=\"aligncenter wp-image-25805 size-full\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all.png\" alt=\"\" width=\"790\" height=\"940\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all.png 790w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all-252x300.png 252w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-all-768x914.png 768w\" sizes=\"auto, (max-width: 790px) 100vw, 790px\" \/><\/a><\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_25800' onClick='GTTabs_show(1,25800)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_25800'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25801\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25801\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1.png\" data-orig-size=\"790,360\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag198-T9-1\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1.png\" class=\"aligncenter wp-image-25801 size-full\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1.png\" alt=\"\" width=\"790\" height=\"360\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1.png 790w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1-300x137.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1-768x350.png 768w\" sizes=\"auto, (max-width: 790px) 100vw, 790px\" \/><\/a><\/p>\n<ol>\n<li>Note-se que a massa de 1 garrafa de \u00f3leo equivale \u00e0 massa de 500 g mais a massa de 1 lata de atum.<\/li>\n<li>No prato esquerdo, da balan\u00e7a \u00e0 esquerda, substituo a garrafa de \u00f3leo pelo peso de 500 g e 1 lata de atum.<br \/>Resultando, assim, a seguinte configura\u00e7\u00e3o de massas: \\(3 \\times l + 500 = 950\\).<\/li>\n<li>Logo, uma lata de atum tem 150 gramas, pois \\(l = \\frac{{950 &#8211; 500}}{3} \\Leftrightarrow l = 150\\).<\/li>\n<\/ol>\n<p>\u00a0<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25803\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25803\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2.png\" data-orig-size=\"790,330\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag198-T9-2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2.png\" class=\"aligncenter wp-image-25803 size-full\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2.png\" alt=\"\" width=\"790\" height=\"330\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2.png 790w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2-300x125.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-2-768x321.png 768w\" sizes=\"auto, (max-width: 790px) 100vw, 790px\" \/><\/a><\/p>\n<ol>\n<li>Se 1 caderno mais um l\u00e1pis custam 8 \u20ac, ent\u00e3o, substituindo na igualdade da direita, o l\u00e1pis e um dos cadernos pelo valor de 8 \u20ac, resulta que 1 caderno mais 8 \u20ac equivale ao valor de 14 \u20ac.<br \/>Isto \u00e9, resulta a seguinte configura\u00e7\u00e3o de valores: \\(c + 8 = 14\\).<\/li>\n<li>Logo, 1 caderno custa 6 \u20ac, pois \\(c = 14 &#8211; 8 \\Leftrightarrow c = 6\\).<\/li>\n<li>E, finalmente, 1 l\u00e1pis custa 2 \u20ac, visto que \\(c + l = 8\\) e \\(c = 6\\).<\/li>\n<\/ol>\n<p>\u00a0<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25804\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25804\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png\" data-orig-size=\"790,240\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag198-T9-3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png\" class=\"aligncenter wp-image-25804 size-full\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png\" alt=\"\" width=\"790\" height=\"240\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png 790w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3-300x91.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3-768x233.png 768w\" sizes=\"auto, (max-width: 790px) 100vw, 790px\" \/><\/a><\/p>\n<ol>\n<li>Na igualdade da esquerda, reparamos que o volume de um copo (<em>p<\/em>) equivale \u00e0 soma dos volumes de um c\u00e1lice (c) e de uma ch\u00e1vena (<em>v<\/em>).<\/li>\n<li>Usando a rela\u00e7\u00e3o anterior no segundo membro da igualdade da direita, podemos substituir o copo por uma ch\u00e1vena e um c\u00e1lice.<\/li>\n<li>Assim, resulta que o volume de 7 c\u00e1lices equivale ao volume de tr\u00eas ch\u00e1venas mais o volume de um c\u00e1lice.<br \/>O que significa que o volume de 6 c\u00e1lices \u00e9 equivalente ao volume de tr\u00eas ch\u00e1venas.<\/li>\n<li>Logo, s\u00e3o necess\u00e1rios 2 c\u00e1lices para encher de \u00e1gua 1 ch\u00e1vena.<\/li>\n<li>E, para encher um copo, ser\u00e3o necess\u00e1rios 3 c\u00e1lices de \u00e1gua.<\/li>\n<\/ol>\n<p>\u00a0<\/p>\n<h6>Isto \u00e9<\/h6>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 50%;\" colspan=\"2\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25804\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25804\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png\" data-orig-size=\"790,240\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag198-T9-3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png\" class=\"alignnone wp-image-25804\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3-300x91.png\" alt=\"\" width=\"720\" height=\"219\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3-300x91.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3-768x233.png 768w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-3.png 790w\" sizes=\"auto, (max-width: 720px) 100vw, 720px\" \/><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\">\\(v + c = p\\)<\/td>\n<td style=\"width: 50%;\">\\(7c = 2v + p\\)<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\">\u00a0<\/td>\n<td style=\"width: 50%;\">\\(7c = 2v + v + c\\)<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\">\u00a0<\/td>\n<td style=\"width: 50%;\">\\(6c = 3v\\)<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\">\u00a0<\/td>\n<td style=\"width: 50%;\"><span style=\"color: #0000ff;\"><strong>\\(2c = v\\)<\/strong><\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\">\\(2c + c = p\\)<\/td>\n<td style=\"width: 50%;\">\u00a0<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 50%;\"><span style=\"color: #0000ff;\"><strong>\\(3c = p\\)<\/strong><\/span><\/td>\n<td style=\"width: 50%;\">\u00a0<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_25800' onClick='GTTabs_show(0,25800)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Observa as imagens e responde \u00e0 quest\u00e3o colocada. Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":25802,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,714],"tags":[424,345,239],"series":[],"class_list":["post-25800","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-equacoes-literais-e-sistemas","tag-8-o-ano","tag-funcao-afim","tag-sistema-de-equacoes"],"views":92,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/05\/8_Pag198-T9-1_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25800","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=25800"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25800\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/25802"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=25800"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=25800"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=25800"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=25800"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}