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{"id":25466,"date":"2023-04-29T12:40:13","date_gmt":"2023-04-29T11:40:13","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=25466"},"modified":"2023-05-05T15:06:50","modified_gmt":"2023-05-05T14:06:50","slug":"dois-baloes-de-s-joao","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=25466","title":{"rendered":"Dois bal\u00f5es de S. Jo\u00e3o"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_25466' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_25466' class='GTTabs_curr'><a  id=\"25466_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_25466' ><a  id=\"25466_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_25466'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Nos gr\u00e1ficos, mostra-se a correspond\u00eancia entre o tempo decorrido desde o lan\u00e7amento e a altura a que se encontram dois bal\u00f5es de S. Jo\u00e3o, tendo um deles sido lan\u00e7ado do ch\u00e3o e outro do cimo de um pr\u00e9dio.<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25468\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25468\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png\" data-orig-size=\"381,353\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag180-2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png\" class=\"aligncenter wp-image-25468\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2-300x278.png\" alt=\"\" width=\"300\" height=\"278\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2-300x278.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png 381w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<ol>\n<li>Uma das fun\u00e7\u00f5es \u00e9 de proporcionalidade direta.<br \/>Identifica-a, justificando, e determina a constante de proporcionalidade.<\/li>\n<li>Qual \u00e9 a fun\u00e7\u00e3o que corresponde ao bal\u00e3o lan\u00e7ado do cimo do pr\u00e9dio? De que altura foi lan\u00e7ado? Justifica.<\/li>\n<li>Determina \\(f\\left( 2 \\right)\\) e explica o seu significado no contexto do problema.<\/li>\n<li>Escreve a express\u00e3o alg\u00e9brica de cada uma das fun\u00e7\u00f5es e explica como procedeste.<\/li>\n<li>O bal\u00e3o representado pela fun\u00e7\u00e3o <em>g<\/em> rebentou ao fim de 9 segundos. A que altura se encontrava nesse momento?<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_25466' onClick='GTTabs_show(1,25466)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_25466'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>Nos gr\u00e1ficos, mostra-se a correspond\u00eancia entre o tempo decorrido desde o lan\u00e7amento e a altura a que se encontram dois bal\u00f5es de S. Jo\u00e3o, tendo um deles sido lan\u00e7ado do ch\u00e3o e outro do cimo de um pr\u00e9dio.<\/p>\n<\/blockquote>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"25468\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=25468\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png\" data-orig-size=\"381,353\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag180-2\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png\" class=\"aligncenter wp-image-25468\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2-300x278.png\" alt=\"\" width=\"300\" height=\"278\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2-300x278.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2.png 381w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p>\u00a0<\/p>\n<ol>\n<li>A fun\u00e7\u00e3o de proporcionalidade direta \u00e9 a fun\u00e7\u00e3o <em>f<\/em>, pois o seu gr\u00e1fico pertence a uma reta n\u00e3o vertical que passa pela origem do referencial. A constante de proporcionalidade \u00e9 \\(f\\left( 1 \\right) = 4\\).<br \/><br \/><\/li>\n<li>\u00c9 a fun\u00e7\u00e3o <em>g<\/em> que corresponde ao bal\u00e3o lan\u00e7ado do cimo do pr\u00e9dio.<br \/>O bal\u00e3o foi lan\u00e7ado a 8 metros de altura, pois \\(g\\left( 0 \\right) = 8\\).<br \/><br \/><\/li>\n<li>Ora, \\(f\\left( 2 \\right) = 8\\).<br \/>No contexto do problema, este valor significa que, ao fim de 2 segundos ap\u00f3s o lan\u00e7amento ao n\u00edvel do ch\u00e3o, o bal\u00e3o atingiu uma altura de 8 metros.<br \/><br \/><\/li>\n<li>Ora, \\(f\\left( x \\right) = 4x\\) e \\(g\\left( x \\right) = 4x + 8\\).<br \/>Para escrever as express\u00f5es, teve-se em conta que as retas que cont\u00eam os dois gr\u00e1ficos possuem declive 4 e ordenadas na origem 0 e 8, respetivamente.<br \/><br \/><\/li>\n<li>Se o bal\u00e3o representado pela fun\u00e7\u00e3o <em>g<\/em> rebentou ao fim de 9 segundo, ent\u00e3o ele encontrava-se nesse momento a \\(g\\left( 9 \\right) = 4 \\times 9 + 8 = 44\\) metros de altura.<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_25466' onClick='GTTabs_show(0,25466)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Nos gr\u00e1ficos, mostra-se a correspond\u00eancia entre o tempo decorrido desde o lan\u00e7amento e a altura a que se encontram dois bal\u00f5es de S. Jo\u00e3o, tendo um deles sido lan\u00e7ado do ch\u00e3o&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":25469,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,709],"tags":[424,345,710,344],"series":[],"class_list":["post-25466","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-graficos-de-funcoes-afins","tag-8-o-ano","tag-funcao-afim","tag-funcao-linear","tag-grafico"],"views":135,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag180-2_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25466","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=25466"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/25466\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/25469"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=25466"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=25466"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=25466"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=25466"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}