{"id":24909,"date":"2023-04-08T19:38:55","date_gmt":"2023-04-08T18:38:55","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=24909"},"modified":"2023-04-08T19:46:34","modified_gmt":"2023-04-08T18:46:34","slug":"qual-e-o-conjnto-solucao-da-equacao","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=24909","title":{"rendered":"Qual \u00e9 o conjnto-solu\u00e7\u00e3o da equa\u00e7\u00e3o?"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_24909' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_24909' class='GTTabs_curr'><a  id=\"24909_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_24909' ><a  id=\"24909_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_24909'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>O conjunto-solu\u00e7\u00e3o da equa\u00e7\u00e3o \\(5{x^2} + x = 0\\) \u00e9:<\/p>\n<p><strong>[A]<\/strong> \\(\\left\\{ {0,\\;\\frac{1}{5}} \\right\\}\\)<br \/><strong>[B]<\/strong> \\(\\left\\{ { &#8211; 6,\\;5} \\right\\}\\)<br \/><strong>[C]<\/strong> \\(\\left\\{ {0,\\;6} \\right\\}\\)<br \/><strong>[D]<\/strong> \\(\\left\\{ { &#8211; \\frac{1}{5},\\;0} \\right\\}\\)<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_24909' onClick='GTTabs_show(1,24909)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_24909'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>O conjunto-solu\u00e7\u00e3o da equa\u00e7\u00e3o \\(5{x^2} + x = 0\\) \u00e9:<\/p>\n<p><strong>[A]<\/strong> \\(\\left\\{ {0,\\;\\frac{1}{5}} \\right\\}\\)<br \/><strong>[B]<\/strong> \\(\\left\\{ { &#8211; 6,\\;5} \\right\\}\\)<br \/><strong>[C]<\/strong> \\(\\left\\{ {0,\\;6} \\right\\}\\)<br \/><strong>[D]<\/strong> \\(\\left\\{ { &#8211; \\frac{1}{5},\\;0} \\right\\}\\)<\/p>\n<\/blockquote>\n<p>A op\u00e7\u00e3o correta \u00e9 <strong>[D]<\/strong> \\(\\left\\{ { &#8211; \\frac{1}{5},\\;0} \\right\\}\\), pois \\(\\left\\{ { &#8211; \\frac{1}{5},\\;0} \\right\\}\\) \u00e9 o conjunto-solu\u00e7\u00e3o da equa\u00e7\u00e3o dada:<\/p>\n<p>\\[\\begin{array}{*{20}{l}}{5{x^2} + x = 0}&amp; \\Leftrightarrow &amp;{x\\left( {5x + 1} \\right) = 0}\\\\{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{c}}{x = 0}&amp; \\vee &amp;{5x + 1 = 0}\\end{array}}\\\\{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{c}}{x = 0}&amp; \\vee &amp;{x = &#8211; \\frac{1}{5}}\\end{array}}\\end{array}\\]<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_24909' onClick='GTTabs_show(0,24909)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado O conjunto-solu\u00e7\u00e3o da equa\u00e7\u00e3o \\(5{x^2} + x = 0\\) \u00e9: [A] \\(\\left\\{ {0,\\;\\frac{1}{5}} \\right\\}\\)[B] \\(\\left\\{ { &#8211; 6,\\;5} \\right\\}\\)[C] \\(\\left\\{ {0,\\;6} \\right\\}\\)[D] \\(\\left\\{ { &#8211; \\frac{1}{5},\\;0} \\right\\}\\) Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt;&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":19175,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,700],"tags":[424,706,198],"series":[],"class_list":["post-24909","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-monomios-e-polinomios","tag-8-o-ano","tag-equacao-incompleta-do-2-o-grau","tag-lei-do-anulamento-do-produto"],"views":137,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat66.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24909","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=24909"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24909\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19175"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=24909"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=24909"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=24909"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=24909"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}