{"id":24818,"date":"2023-04-04T11:53:16","date_gmt":"2023-04-04T10:53:16","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=24818"},"modified":"2023-04-04T12:10:31","modified_gmt":"2023-04-04T11:10:31","slug":"tres-quadrados","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=24818","title":{"rendered":"Tr\u00eas quadrados"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_24818' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_24818' class='GTTabs_curr'><a  id=\"24818_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_24818' ><a  id=\"24818_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_24818'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>A parte da figura sombreada a verde tem 22 cm<sup>2<\/sup> de \u00e1rea.<br \/>Qual \u00e9 o comprimento, em cent\u00edmetros, do lado do quadrado [ABCD]? Explica a tua resposta.<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"24820\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=24820\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png\" data-orig-size=\"433,459\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag149-20\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png\" class=\"aligncenter wp-image-24820\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20-283x300.png\" alt=\"\" width=\"300\" height=\"318\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20-283x300.png 283w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png 433w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_24818' onClick='GTTabs_show(1,24818)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_24818'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>A parte da figura sombreada a verde tem 22 cm<sup>2<\/sup> de \u00e1rea.<br \/>Qual \u00e9 o comprimento, em cent\u00edmetros, do lado do quadrado [ABCD]? Explica a tua resposta.<\/p>\n<\/blockquote>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"24820\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=24820\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png\" data-orig-size=\"433,459\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag149-20\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png\" class=\"aligncenter wp-image-24820\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20-283x300.png\" alt=\"\" width=\"300\" height=\"318\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20-283x300.png 283w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20.png 433w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p>\u00a0<\/p>\n<p>Designemos por \\(x\\) o comprimento, em cent\u00edmetros, do lado do quadrado mais pequeno.<\/p>\n<p>Como a \u00e1rea do quadrado [ABCD] \u00e9 a soma das \u00e1reas dos quadrados pequeno e m\u00e9dio com a parte da figura sombreada a verde, vem:<\/p>\n<p>\\[\\begin{array}{*{20}{l}}{{{\\left( {4 + x} \\right)}^2} = {4^2} + {x^2} + 22}&amp; \\Leftrightarrow &amp;{16 + 8x + {x^2} = 16 + {x^2} + 22}\\\\{}&amp; \\Leftrightarrow &amp;{8x = 22}\\\\{}&amp; \\Leftrightarrow &amp;{x = \\frac{{11}}{4}}\\\\{}&amp; \\Leftrightarrow &amp;{x = 2,75}\\end{array}\\]<\/p>\n<p>Portanto, o lado do quadrado [ABCD] tem 6,75 cm de comprimento.<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_24818' onClick='GTTabs_show(0,24818)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado A parte da figura sombreada a verde tem 22 cm2 de \u00e1rea.Qual \u00e9 o comprimento, em cent\u00edmetros, do lado do quadrado [ABCD]? Explica a tua resposta. Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":24821,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_post_was_ever_published":false},"categories":[100,97,700],"tags":[424,706,198],"series":[],"class_list":["post-24818","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-monomios-e-polinomios","tag-8-o-ano","tag-equacao-incompleta-do-2-o-grau","tag-lei-do-anulamento-do-produto"],"views":70,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/04\/8_Pag149-20_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24818","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=24818"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24818\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/24821"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=24818"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=24818"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=24818"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=24818"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}