O conjunto-solu\u00e7\u00e3o das equa\u00e7\u00f5es est\u00e1 apresentado abaixo.<\/p>\n\n\n\n\n\n\n\n\n\n\n

a)<\/td>\n	\\[\\begin{array}{*{20}{l}}{x\\left( {x – 1} \\right) = 0}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = 0}& \\vee &{x – 1 = 0}\\end{array}}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = 0}& \\vee &{x = 1}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ {0,\\;1} \\right\\}\\]<\/td>\n<\/tr>\n
b)<\/td>\n	\\[\\begin{array}{*{20}{l}}{\\left( {a – 1} \\right)\\left( {a + 1} \\right) = 0}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{a – 1 = 0}& \\vee &{a + 1 = 0}\\end{array}}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{a = 1}& \\vee &{a = – 1}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ { – 1,\\;1} \\right\\}\\]<\/td>\n<\/tr>\n
c)<\/td>\n	\\[\\begin{array}{*{20}{l}}{{x^2} – 2x = 0}& \\Leftrightarrow &{x\\left( {x – 2} \\right) = 0}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = 0}& \\vee &{x – 2 = 0}\\end{array}}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = 0}& \\vee &{x = 2}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ {0,\\;2} \\right\\}\\]<\/td>\n<\/tr>\n
d)<\/td>\n	\\[\\begin{array}{*{20}{l}}{2{x^2} = 32}& \\Leftrightarrow &{{x^2} = 16}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = – 4}& \\vee &{x = 4}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ { – 4,\\;4} \\right\\}\\]<\/td>\n<\/tr>\n
e)<\/td>\n	\\[\\begin{array}{*{20}{l}}{{c^2} – 0,25 = 0}& \\Leftrightarrow &{{c^2} = 0,25}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = – 0,5}& \\vee &{x = 0,5}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ { – 0,5;\\;0,5} \\right\\}\\]<\/td>\n<\/tr>\n
f)<\/td>\n	\\[\\begin{array}{*{20}{l}}{{x^2} = 0,01}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = – 0,1}& \\vee &{x = 0,1}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ { – 0,1;\\;0,1} \\right\\}\\]<\/td>\n<\/tr>\n
g)<\/td>\n	\\[\\begin{array}{*{20}{l}}{{y^3} – 4y = 0}& \\Leftrightarrow &{y\\left( {{y^2} – 4} \\right) = 0}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{y = 0}& \\vee &{{y^2} – 4 = 0}\\end{array}}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{y = 0}& \\vee &{{y^2} = 4}\\end{array}}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{l}}{y = 0}& \\vee &{y = – 2}& \\vee &{y = 2}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ { – 2,\\;0,\\;2} \\right\\}\\]<\/td>\n<\/tr>\n
h)<\/td>\n	\\[\\begin{array}{*{20}{l}}{{x^2} – 256 = 0}& \\Leftrightarrow &{{x^2} = 256}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = – \\sqrt {256} }& \\vee &{x = \\sqrt {256} }\\end{array}}\\\\{}& \\Leftrightarrow &{\\begin{array}{*{20}{c}}{x = – 16}& \\vee &{x = 16}\\end{array}}\\end{array}\\]<\/td>\n	\\[S = \\left\\{ { – 16,\\;16} \\right\\}\\]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n \u00a0<\/p>\n << Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":" Enunciado Resolu\u00e7\u00e3o Enunciado Determina o conjunto-solu\u00e7\u00e3o das seguintes equa\u00e7\u00f5es. a) \\(x\\left( {x – 1} \\right) = 0\\) b) \\(\\left( {a – 1} \\right)\\left( {a + 1} \\right) = 0\\) c) \\({x^2} – 2x =...<\/p>\n","protected":false},"author":1,"featured_media":19175,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,700],"tags":[424,706,198],"series":[],"class_list":["post-24804","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-monomios-e-polinomios","tag-8-o-ano","tag-equacao-incompleta-do-2-o-grau","tag-lei-do-anulamento-do-produto"],"views":117,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat66.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24804","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=24804"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24804\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19175"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=24804"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=24804"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=24804"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=24804"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}