{"id":24610,"date":"2023-03-10T18:49:04","date_gmt":"2023-03-10T18:49:04","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=24610"},"modified":"2023-03-10T21:15:37","modified_gmt":"2023-03-10T21:15:37","slug":"um-edificio-de-escritorios","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=24610","title":{"rendered":"Um edif\u00edcio de escrit\u00f3rios"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_24610' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_24610' class='GTTabs_curr'><a  id=\"24610_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_24610' ><a  id=\"24610_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_24610'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"24611\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=24611\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png\" data-orig-size=\"385,248\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag144-T11\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png\" class=\"alignright wp-image-24611\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11-300x193.png\" alt=\"\" width=\"320\" height=\"206\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11-300x193.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png 385w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><\/a>Um edif\u00edcio de escrit\u00f3rios tem uma fachada com vidros quadrados.<\/p>\n<p>Sabendo que a 100 m<sup>2<\/sup> de fachada correspondem 400 quadrados de vidro, quanto mede, em cm, o lado de cada vidro?<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_24610' onClick='GTTabs_show(1,24610)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_24610'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"24611\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=24611\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png\" data-orig-size=\"385,248\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag144-T11\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png\" class=\"alignright wp-image-24611\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11-300x193.png\" alt=\"\" width=\"320\" height=\"206\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11-300x193.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11.png 385w\" sizes=\"auto, (max-width: 320px) 100vw, 320px\" \/><\/a>Um edif\u00edcio de escrit\u00f3rios tem uma fachada com vidros quadrados.<\/p>\n<p>Sabendo que a 100 m<sup>2<\/sup> de fachada correspondem 400 quadrados de vidro, quanto mede, em cm, o lado de cada vidro?<\/p>\n<\/blockquote>\n<p>\u00a0<\/p>\n<p>Como 400 quadrados de vidro correspondem a 100 m<sup>2<\/sup> de fachada, ent\u00e3o 4 quadrados de vidro correspondem a 1 m<sup>2<\/sup>. Consequentemente, cada quadrado de vidro tem 50 cm de lado.<\/p>\n<p>\u00a0<\/p>\n<h6>Resolu\u00e7\u00e3o alternativa:<\/h6>\n<p>Designando por \\(x\\) o comprimento, em metros, do lado de cada quadrado de vidro, vem:<\/p>\n<p>\\[\\begin{array}{*{20}{l}}{400{x^2} = 100}&amp; \\Leftrightarrow &amp;{{x^2} = \\frac{{100}}{{400}}}\\\\{}&amp; \\Leftrightarrow &amp;{{x^2} = \\frac{1}{4}}\\end{array}\\]<\/p>\n<p>Portanto, cada quadrado de vidro tem 50 cm de lado.<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_24610' onClick='GTTabs_show(0,24610)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Um edif\u00edcio de escrit\u00f3rios tem uma fachada com vidros quadrados. Sabendo que a 100 m2 de fachada correspondem 400 quadrados de vidro, quanto mede, em cm, o lado de cada vidro?&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":24612,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,700],"tags":[424,706,705],"series":[],"class_list":["post-24610","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-monomios-e-polinomios","tag-8-o-ano","tag-equacao-incompleta-do-2-o-grau","tag-polinomios"],"views":109,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/03\/8_Pag144-T11_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24610","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=24610"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24610\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/24612"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=24610"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=24610"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=24610"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=24610"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}