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{"id":24444,"date":"2023-02-08T18:36:58","date_gmt":"2023-02-08T18:36:58","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=24444"},"modified":"2023-02-17T08:40:40","modified_gmt":"2023-02-17T08:40:40","slug":"considera-o-seguinte-triangulo-equilatero","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=24444","title":{"rendered":"Considera o seguinte tri\u00e2ngulo equil\u00e1tero"},"content":{"rendered":"\n<p><ul id='GTTabs_ul_24444' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_24444' class='GTTabs_curr'><a  id=\"24444_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_24444' ><a  id=\"24444_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_24444'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Considera o seguinte tri\u00e2ngulo equil\u00e1tero.<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"24447\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=24447\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\" data-orig-size=\"170,153\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag126-3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\" class=\"aligncenter wp-image-24447 size-full\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\" alt=\"\" width=\"170\" height=\"153\" \/><\/a><\/p>\n<ol>\n<li>Escreve, na forma can\u00f3nica, o mon\u00f3mio que representa o per\u00edmetro do tri\u00e2ngulo.<\/li>\n<li>Para \\(x = 0,5\\), calcula a medida do comprimento de cada lado e o per\u00edmetro do tri\u00e2ngulo.<\/li>\n<li>Para \\(x = \\frac{2}{3}\\), determina o per\u00edmetro do tri\u00e2ngulo.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_24444' onClick='GTTabs_show(1,24444)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_24444'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<blockquote>\n<p>Considera o seguinte tri\u00e2ngulo equil\u00e1tero.<\/p>\n<\/blockquote>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"24447\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=24447\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\" data-orig-size=\"170,153\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"8_Pag126-3\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\" class=\"aligncenter wp-image-24447 size-full\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3.png\" alt=\"\" width=\"170\" height=\"153\" \/><\/a><\/p>\n<ol>\n<li>\n<blockquote>Escreve, na forma can\u00f3nica, o mon\u00f3mio que representa o per\u00edmetro do tri\u00e2ngulo.<\/blockquote>\n<\/li>\n<li>\n<blockquote>Para \\(x = 0,5\\), calcula a medida do comprimento de cada lado e o per\u00edmetro do tri\u00e2ngulo.<\/blockquote>\n<\/li>\n<li>\n<blockquote>Para \\(x = \\frac{2}{3}\\), determina o per\u00edmetro do tri\u00e2ngulo.<\/blockquote>\n<\/li>\n<\/ol>\n<p>\u00a0<\/p>\n<ol>\n<li>\\(P = 2x + 2x + 2x = 6x\\).<br \/><br \/><\/li>\n<li>Ora, \\(P = 6x\\) e \\(l = 2x\\).<br \/>Assim, para \\(x = 0,5\\), vem: \\(l = 2 \\times 0,5 = 1\\) e \\(P = 6 \\times 0,5 = 3\\).<br \/><br \/><\/li>\n<li>Para \\(x = \\frac{2}{3}\\), temos: \\(P = 6 \\times \\frac{2}{3} = 2 \\times 2 = 4\\).<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_24444' onClick='GTTabs_show(0,24444)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Considera o seguinte tri\u00e2ngulo equil\u00e1tero. Escreve, na forma can\u00f3nica, o mon\u00f3mio que representa o per\u00edmetro do tri\u00e2ngulo. Para \\(x = 0,5\\), calcula a medida do comprimento de cada lado e o&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":24448,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,700],"tags":[424,194,703,704],"series":[],"class_list":["post-24444","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-monomios-e-polinomios","tag-8-o-ano","tag-monomios","tag-monomios-semelhantes","tag-operacoes-com-monomios"],"views":80,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2023\/02\/8_Pag126-3_520X245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24444","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=24444"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/24444\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/24448"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=24444"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=24444"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=24444"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=24444"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}