\nEnnciado<\/b><\/span><\/p>\n
Calcula o valor exato de:<\/p>\n
\n
\\(\\sqrt 3 \\times \\left( {1 + \\frac{3}{{\\sqrt 3 }}} \\right)\\)<\/li>\n
\\({\\left[ {{{\\left( {\\sqrt 5 } \\right)}^2}} \\right]^2}\\)<\/li>\n
\\(\\frac{{7\\pi – 3\\pi }}{{2\\pi }} \\times \\frac{{{{\\left( {6\\pi } \\right)}^2}}}{{2\\pi }}\\)<\/li>\n<\/ol>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
\n
Calcula o valor exato de:<\/p>\n<\/blockquote>\n
\n
\n
\\(\\sqrt 3 \\times \\left( {1 + \\frac{3}{{\\sqrt 3 }}} \\right)\\)<\/blockquote>\n<\/li>\n
\n
\\({\\left[ {{{\\left( {\\sqrt 5 } \\right)}^2}} \\right]^2}\\)<\/blockquote>\n<\/li>\n
\n
\\(\\frac{{7\\pi – 3\\pi }}{{2\\pi }} \\times \\frac{{{{\\left( {6\\pi } \\right)}^2}}}{{2\\pi }}\\)<\/blockquote>\n<\/li>\n<\/ol>\n
\u00a0<\/p>\n
\n
\\(\\sqrt 3 \\times \\left( {1 + \\frac{3}{{\\sqrt 3 }}} \\right) = \\sqrt 3 + \\frac{{3\\sqrt 3 }}{{\\sqrt 3 }} = \\sqrt 3 + 3\\)

<\/li>\n
\\({\\left[ {{{\\left( {\\sqrt 5 } \\right)}^2}} \\right]^2} = {\\left( 5 \\right)^2} = 25\\)

<\/li>\n
\\[\\frac{{7\\pi – 3\\pi }}{{2\\pi }} \\times \\frac{{{{\\left( {6\\pi } \\right)}^2}}}{{2\\pi }} = \\frac{{\\left( {7 – 3} \\right)\\pi }}{{2\\pi }} \\times \\frac{{36{\\pi ^2}}}{{2\\pi }} = \\frac{{4\\pi }}{{2\\pi }} \\times \\frac{{36{\\pi ^2}}}{{2\\pi }} = 2 \\times 18\\pi = 36\\pi \\]<\/li>\n<\/ol>\n
<< Ennciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Ennciado Resolu\u00e7\u00e3o Ennciado Calcula o valor exato de: \\(\\sqrt 3 \\times \\left( {1 + \\frac{3}{{\\sqrt 3 }}} \\right)\\) \\({\\left[ {{{\\left( {\\sqrt 5 } \\right)}^2}} \\right]^2}\\) \\(\\frac{{7\\pi – 3\\pi }}{{2\\pi }} \\times \\frac{{{{\\left( {6\\pi }...<\/p>\n","protected":false},"author":1,"featured_media":19188,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,664],"tags":[424,450],"series":[],"class_list":["post-23002","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-numeros-reais","tag-8-o-ano","tag-operacoes-com-numeros-reais"],"views":306,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat74.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/23002","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=23002"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/23002\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19188"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=23002"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=23002"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=23002"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=23002"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}