\nEnunciado<\/b><\/span><\/p>\n
Considera \\(A = 7 \\times {10^5}\\) e \\(B = 5 \\times {10^{ – 3}}\\).<\/p>\n
\n
Indica o n\u00famero maior.<\/li>\n
Calcula \\(A \\times B\\) em nota\u00e7\u00e3o cient\u00edfica.<\/li>\n
Calcula \\(\\frac{A}{B}\\) em nota\u00e7\u00e3o cient\u00edfica.<\/li>\n
Determina 30% de \\(A\\) e escreve o n\u00famero em nota\u00e7\u00e3o cient\u00edfica.<\/li>\n
Determina \\(\\frac{3}{{25}}B\\) e escreve o n\u00famero em nota\u00e7\u00e3o cient\u00edfica.<\/li>\n<\/ol>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
\n
Considera \\(A = 7 \\times {10^5}\\) e \\(B = 5 \\times {10^{ – 3}}\\).<\/p>\n<\/blockquote>\n
\n

O maior n\u00famero \u00e9 \\(A = 7 \\times {10^5}\\).

<\/li>\n

\\(A \\times B = 7 \\times {10^5} \\times 5 \\times {10^{ – 3}} = \\left( {7 \\times 5} \\right) \\times \\left( {{{10}^5} \\times {{10}^{ – 3}}} \\right) = 35 \\times {10^2} = 3,5 \\times {10^3}\\)

<\/li>\n

\\[\\frac{A}{B} = \\frac{{7 \\times {{10}^5}}}{{5 \\times {{10}^{ – 3}}}} = \\frac{7}{{5 \\times }} \\times \\frac{{{{10}^5}}}{{{{10}^{ – 3}}}} = 1,4 \\times {10^8}\\]<\/li>\n

\\(30\\% \\times A = 0,3 \\times 7 \\times {10^5} = \\left( {0,3 \\times 7} \\right) \\times {10^5} = 2,1 \\times {10^5}\\)

<\/li>\n

\\(\\frac{3}{{25}}B = \\frac{3}{{25}} \\times 5 \\times {10^{ – 3}} = \\frac{3}{5} \\times {10^{ – 3}} = 0,6 \\times {10^{ – 3}} = 6 \\times {10^{ – 4}}\\)<\/li>\n<\/ol>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Considera \\(A = 7 \\times {10^5}\\) e \\(B = 5 \\times {10^{ – 3}}\\). Indica o n\u00famero maior. Calcula \\(A \\times B\\) em nota\u00e7\u00e3o cient\u00edfica. Calcula \\(\\frac{A}{B}\\) em nota\u00e7\u00e3o cient\u00edfica. Determina...<\/p>\n","protected":false},"author":1,"featured_media":19189,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,664],"tags":[424,143],"series":[],"class_list":["post-22757","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-numeros-reais","tag-8-o-ano","tag-notacao-cientifica"],"views":235,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat75.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/22757","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=22757"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/22757\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19189"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=22757"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=22757"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=22757"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=22757"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}