\nEnunciado<\/b><\/span><\/p>\n
Calcula o valor num\u00e9rico de cada uma das seguintes express\u00f5es:<\/p>\n\n\n\n
\n
\n
\\({0^3}\\)<\/li>\n
\\({7^2}\\)<\/li>\n
\\({\\left( { – 7} \\right)^2}\\)<\/li>\n
\\({10^2}\\)<\/li>\n
\\({\\left( { – 10} \\right)^3}\\)<\/li>\n
\\( – {10^2}\\)<\/li>\n
\\({\\left( {\\frac{3}{5}} \\right)^2}\\)<\/li>\n<\/ol>\n<\/td>\n
\n
\n
\\({\\left( { – \\frac{3}{5}} \\right)^2}\\)<\/li>\n
\\({\\left( { – \\frac{3}{5}} \\right)^3}\\)<\/li>\n
\\({\\left( {\\frac{3}{5}} \\right)^3}\\)<\/li>\n
\\({\\left( { – 0,3} \\right)^5}\\)<\/li>\n
\\({\\left( { – 0,3} \\right)^4}\\)<\/li>\n
\\({0,3^5}\\)<\/li>\n
\\({0,3^4}\\)<\/li>\n<\/ol>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/span>
<\/p>\n
\n
\\({0^3} = 0 \\times 0 \\times 0 = 0\\)

<\/li>\n
\\({7^2} = 7 \\times 7 = 49\\)

<\/li>\n
\\({\\left( { – 7} \\right)^2} = – 7 \\times \\left( { – 7} \\right) = 49\\)

<\/li>\n
\\({10^2} = 10 \\times 10 = 100\\)

<\/li>\n
\\({\\left( { – 10} \\right)^3} = – 10 \\times \\left( { – 10} \\right) \\times \\left( { – 10} \\right) = – 1000\\)

<\/li>\n
\\( – {10^2} = – \\left( {{{10}^2}} \\right) = – \\left( {10 \\times 10} \\right) = – 100\\)

<\/li>\n
\\({\\left( {\\frac{3}{5}} \\right)^2} = \\frac{3}{5} \\times \\frac{3}{5} = \\frac{9}{{25}}\\)

<\/li>\n
\\({\\left( { – \\frac{3}{5}} \\right)^2} = – \\frac{3}{5} \\times \\left( { – \\frac{3}{5}} \\right) = \\frac{9}{{25}}\\)

<\/li>\n
\\({\\left( { – \\frac{3}{5}} \\right)^3} = – \\frac{3}{5} \\times \\left( { – \\frac{3}{5}} \\right) \\times \\left( { – \\frac{3}{5}} \\right) = – \\frac{{27}}{{125}}\\)

<\/li>\n
\\({\\left( {\\frac{3}{5}} \\right)^3} = \\frac{3}{5} \\times \\frac{3}{5} \\times \\frac{3}{5} = \\frac{{27}}{{125}}\\)

<\/li>\n
\\({\\left( { – 0,3} \\right)^5} = – 0,3 \\times \\underbrace {\\left( { – 0,3} \\right) \\times \\left( { – 0,3} \\right)}_{0,09} \\times \\underbrace {\\left( { – 0,3} \\right) \\times \\left( { – 0,3} \\right)}_{0,09} = – 0,3 \\times 0,0081 = – 0,00243\\)

<\/li>\n
\\({\\left( { – 0,3} \\right)^4} = – 0,3 \\times \\left( { – 0,3} \\right) \\times \\left( { – 0,3} \\right) \\times \\left( { – 0,3} \\right) = 0,0081\\)

<\/li>\n
\\({0,3^5} = 0,3 \\times 0,3 \\times 0,3 \\times 0,3 \\times 0,3 = 0,00243\\)

<\/li>\n
\\({0,3^4} = 0,3 \\times 0,3 \\times 0,3 \\times 0,3 = 0,0081\\)<\/li>\n<\/ol>\n
\u00a0<\/p>\n
Repetindo a quest\u00e3o 13 e passando a d\u00edzima a fra\u00e7\u00e3o irredut\u00edvel, vem:<\/p>\n
\\({0,3^5} = {\\left( {\\frac{3}{{10}}} \\right)^5} = \\frac{3}{{10}} \\times \\frac{3}{{10}} \\times \\frac{3}{{10}} \\times \\frac{3}{{10}} \\times \\frac{3}{{10}} = \\frac{{243}}{{100000}} = 0,00243\\)<\/p>\n
\u00a0<\/p>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Calcula o valor num\u00e9rico de cada uma das seguintes express\u00f5es: \\({0^3}\\) \\({7^2}\\) \\({\\left( { – 7} \\right)^2}\\) \\({10^2}\\) \\({\\left( { – 10} \\right)^3}\\) \\( – {10^2}\\) \\({\\left( {\\frac{3}{5}} \\right)^2}\\) \\({\\left( {...<\/p>\n","protected":false},"author":1,"featured_media":19309,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[100,97,664],"tags":[424,142],"series":[],"class_list":["post-22272","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-8--ano","category-aplicando","category-numeros-reais","tag-8-o-ano","tag-potencias"],"views":274,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat113.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/22272","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=22272"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/22272\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19309"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=22272"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=22272"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=22272"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=22272"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}