{"id":14152,"date":"2018-03-13T00:10:00","date_gmt":"2018-03-13T00:10:00","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=14152"},"modified":"2022-01-11T11:14:41","modified_gmt":"2022-01-11T11:14:41","slug":"as-razoes-trigonometricas-dos-angulos-de-30circ-45circ-e-60circ","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=14152","title":{"rendered":"As raz\u00f5es trigonom\u00e9tricas dos \u00e2ngulos de \\(30^\\circ \\), \\(45^\\circ \\) e \\(60^\\circ \\)"},"content":{"rendered":"<p><ul id='GTTabs_ul_14152' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_14152' class='GTTabs_curr'><a  id=\"14152_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_14152' ><a  id=\"14152_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<li id='GTTabs_li_2_14152' ><a  id=\"14152_2\" onMouseOver=\"GTTabsShowLinks('S\u00edntese'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>S\u00edntese<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_14152'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<ol>\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"14155\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=14155\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\" data-orig-size=\"282,275\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Quadrado\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\" class=\"alignright wp-image-14155\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\" alt=\"\" width=\"200\" height=\"195\" \/><\/a>Na figura, [<em>DU<\/em>] \u00e9 uma diagonal do quadrado de lado <em>a<\/em>.<\/li>\n<\/ol>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>Qual \u00e9 a medida da amplitude do \u00e2ngulo <em>UDA<\/em>? Justifica.<\/li>\n<li>Calcula, a partir do quadrado de lado <em>a<\/em>, os valores exatos de\u00a0\\({\\mathop{\\rm sen}\\nolimits} 45^\\circ \\),\u00a0\\(\\cos 45^\\circ \\) e\u00a0\\({\\mathop{\\rm tg}\\nolimits} 45^\\circ \\).<\/li>\n<\/ol>\n<ol start=\"2\">\n<li>Considera o seguinte tri\u00e2ngulo equil\u00e1tero [<em>ABC<\/em>] de lado <em>x<\/em> no qual foi tra\u00e7ada uma das suas alturas.<\/li>\n<\/ol>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>Escreve o comprimento da altura, <em>h<\/em>, do tri\u00e2ngulo em fun\u00e7\u00e3o de <em>x<\/em>.<\/li>\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"14157\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=14157\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\" data-orig-size=\"264,253\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Tri\u00e2ngulo\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\" class=\"alignright wp-image-14157\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\" alt=\"\" width=\"200\" height=\"192\" \/><\/a>Qual \u00e9 a medida da amplitude do \u00e2ngulo interno <em>ABC<\/em> do tri\u00e2ngulo? Justifica.<\/li>\n<li>Qual \u00e9 a medida da amplitude do \u00e2ngulo <em>BAD<\/em>? Justifica.<\/li>\n<li>Calcula, a partir do tri\u00e2ngulo [<em>ADC<\/em>], os valores exatos de\u00a0\\({\\mathop{\\rm sen}\\nolimits} 60^\\circ \\),\u00a0\\(\\cos 60^\\circ \\) e\u00a0\\({\\mathop{\\rm tg}\\nolimits} 60^\\circ \\).<\/li>\n<li>Calcula, a partir do tri\u00e2ngulo [<em>ADC<\/em>], os valores exatos de\u00a0\\({\\mathop{\\rm sen}\\nolimits} 30^\\circ \\),\u00a0\\(\\cos 30^\\circ \\) e\u00a0\\({\\mathop{\\rm tg}\\nolimits} 30^\\circ \\).<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_14152' onClick='GTTabs_show(1,14152)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_14152'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"14155\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=14155\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\" data-orig-size=\"282,275\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Quadrado\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\" class=\"alignright wp-image-14155\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-1.png\" alt=\"\" width=\"200\" height=\"195\" \/><\/a>Na figura, [<em>DU<\/em>] \u00e9 uma diagonal do quadrado de lado <em>a<\/em>.<\/li>\n<\/ol>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>Qual \u00e9 a medida da amplitude do \u00e2ngulo <em>UDA<\/em>? Justifica.<br \/><span style=\"color: #0000ff;\">A amplitude do \u00e2ngulo <em>UDA<\/em> \u00e9 45 graus, pois o tri\u00e2ngulo [<em>UDA<\/em>] \u00e9 ret\u00e2ngulo is\u00f3sceles.<\/span><\/li>\n<li>Calcula, a partir do quadrado de lado <em>a<\/em>, os valores exatos de\u00a0\\({\\mathop{\\rm sen}\\nolimits} 45^\\circ \\),\u00a0\\(\\cos 45^\\circ \\) e\u00a0\\({\\mathop{\\rm tg}\\nolimits} 45^\\circ \\).<\/li>\n<\/ol>\n<ul>\n<li><span style=\"color: #0000ff;\">\\({\\mathop{\\rm sen}\\nolimits} 45^\\circ = \\frac{{\\overline {UA} }}{{\\overline {UD} }} = \\frac{a}{{a\\sqrt 2 }} = \\frac{1}{{\\sqrt 2 }} \\times \\frac{{\\sqrt 2 }}{{\\sqrt 2 }} = \\frac{{\\sqrt 2 }}{2}\\)<\/span><\/li>\n<li><span style=\"color: #0000ff;\">\\(\\cos 45^\\circ = \\frac{{\\overline {AD} }}{{\\overline {UD} }} = \\frac{a}{{a\\sqrt 2 }} = \\frac{1}{{\\sqrt 2 }} \\times \\frac{{\\sqrt 2 }}{{\\sqrt 2 }} = \\frac{{\\sqrt 2 }}{2}\\)<\/span><\/li>\n<li><span style=\"color: #0000ff;\">\\({\\mathop{\\rm tg}\\nolimits} 45^\\circ = \\frac{{\\overline {UA} }}{{\\overline {AD} }} = \\frac{a}{a} = 1\\)<br \/>\u00ad<br \/><\/span><\/li>\n<\/ul>\n<ol start=\"2\">\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"14157\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=14157\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\" data-orig-size=\"264,253\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Tri\u00e2ngulo\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\" class=\"alignright wp-image-14157\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6-2.png\" alt=\"\" width=\"200\" height=\"192\" \/><\/a>Considera o seguinte tri\u00e2ngulo equil\u00e1tero [<em>ABC<\/em>] de lado <em>x<\/em> no qual foi tra\u00e7ada uma das suas alturas.<\/li>\n<\/ol>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>Escreve o comprimento da altura, <em>h<\/em>, do tri\u00e2ngulo em fun\u00e7\u00e3o de <em>x<\/em>.<br \/><span style=\"color: #0000ff;\">Por aplica\u00e7\u00e3o do Teorema de Pit\u00e1goras no tri\u00e2ngulo ret\u00e2ngulo [ACD], vem:<\/span><br \/><span style=\"color: #0000ff;\">\\[h = \\sqrt {{{\\overline {AC} }^2} &#8211; {{\\left( {\\frac{{\\overline {BD} }}{2}} \\right)}^2}} = \\sqrt {{x^2} &#8211; {{\\left( {\\frac{x}{2}} \\right)}^2}} = \\sqrt {{x^2} &#8211; {{\\frac{x}{4}}^2}} = \\sqrt {\\frac{{3{x^2}}}{4}} = \\frac{{\\sqrt 3 }}{2}x\\]<\/span><\/li>\n<li>Qual \u00e9 a medida da amplitude do \u00e2ngulo interno <em>ABC<\/em> do tri\u00e2ngulo? Justifica.<br \/><span style=\"color: #0000ff;\">A amplitude do \u00e2ngulo interno ABC \u00e9 60 graus, pois o tri\u00e2ngulo [ABC] \u00e9 equi\u00e2ngulo, visto ser equil\u00e1tero.<\/span><\/li>\n<li>Qual \u00e9 a medida da amplitude do \u00e2ngulo <em>BAD<\/em>? Justifica.<br \/><span style=\"color: #0000ff;\">Como a soma das amplitudes dos \u00e2ngulos internos de um tri\u00e2ngulo \u00e9 igual a 180 graus, vem:<\/span><br \/><span style=\"color: #0000ff;\">\\(B\\widehat AD = 180^\\circ &#8211; \\left( {A\\widehat BD + A\\widehat DB} \\right) = 180^\\circ &#8211; \\left( {60^\\circ + 90^\\circ } \\right) = 30^\\circ \\).<\/span><\/li>\n<li>Calcula, a partir do tri\u00e2ngulo [<em>ADC<\/em>], os valores exatos de\u00a0\\({\\mathop{\\rm sen}\\nolimits} 60^\\circ \\),\u00a0\\(\\cos 60^\\circ \\) e\u00a0\\({\\mathop{\\rm tg}\\nolimits} 60^\\circ \\).<\/li>\n<\/ol>\n<ul>\n<li><span style=\"color: #0000ff;\">\\({\\mathop{\\rm sen}\\nolimits} 60^\\circ = \\frac{{\\overline {AD} }}{{\\overline {AB} }} = \\frac{{\\frac{{\\sqrt 3 }}{2}x}}{x} = \\frac{{\\sqrt 3 }}{2}\\)<\/span><\/li>\n<li><span style=\"color: #0000ff;\">\\(\\cos 60^\\circ = \\frac{{\\overline {BD} }}{{\\overline {AB} }} = \\frac{{\\frac{x}{2}}}{x} = \\frac{1}{2}\\)<\/span><\/li>\n<li><span style=\"color: #0000ff;\">\\({\\mathop{\\rm tg}\\nolimits} 60^\\circ = \\frac{{\\overline {AD} }}{{\\overline {BD} }} = \\frac{{\\frac{{\\sqrt 3 }}{2}x}}{{\\frac{x}{2}}} = \\sqrt 3 \\)<\/span><\/li>\n<\/ul>\n<ol style=\"list-style-type: lower-alpha;\" start=\"5\">\n<li>Calcula, a partir do tri\u00e2ngulo [<em>ADC<\/em>], os valores exatos de\u00a0\\({\\mathop{\\rm sen}\\nolimits} 30^\\circ \\),\u00a0\\(\\cos 30^\\circ \\) e\u00a0\\({\\mathop{\\rm tg}\\nolimits} 30^\\circ \\).<\/li>\n<\/ol>\n<ul>\n<li><span style=\"color: #0000ff;\">\\({\\mathop{\\rm sen}\\nolimits} 30^\\circ = \\frac{{\\overline {BD} }}{{\\overline {AB} }} = \\frac{{\\frac{x}{2}}}{x} = \\frac{1}{2}\\)<\/span><\/li>\n<li><span style=\"color: #0000ff;\">\\(\\cos 30^\\circ = \\frac{{\\overline {AD} }}{{\\overline {AB} }} = \\frac{{\\frac{{\\sqrt 3 }}{2}x}}{x} = \\frac{{\\sqrt 3 }}{2}\\)<\/span><\/li>\n<li><span style=\"color: #0000ff;\">\\({\\mathop{\\rm tg}\\nolimits} 30^\\circ = \\frac{{\\overline {BD} }}{{\\overline {AD} }} = \\frac{{\\frac{x}{2}}}{{\\frac{{\\sqrt 3 }}{2}x}} = \\frac{x}{2} \\times \\frac{2}{{x\\sqrt 3 }} = \\frac{1}{{\\sqrt 3 }} \\times \\frac{{\\sqrt 3 }}{{\\sqrt 3 }} = \\frac{{\\sqrt 3 }}{3}\\)<\/span><\/li>\n<\/ul>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_14152' onClick='GTTabs_show(0,14152)'>&lt;&lt; Enunciado<\/a><\/span><span class='GTTabs_nav_next'><a href='#GTTabs_ul_14152' onClick='GTTabs_show(2,14152)'>S\u00edntese &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_2_14152'>\n<span class='GTTabs_titles'><b>S\u00edntese<\/b><\/span><\/p>\n<blockquote>\n<p style=\"text-align: center;\"><strong>As raz\u00f5es trigonom\u00e9tricas dos \u00e2ngulos de \\(30^\\circ \\), \\(45^\\circ \\) e \\(60^\\circ \\)<\/strong><\/p>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 25%;\">\\(\\alpha \\)<\/td>\n<td style=\"width: 25%;\">\\(30^\\circ \\)<\/td>\n<td style=\"width: 25%;\">\\(45^\\circ \\)<\/td>\n<td style=\"width: 25%;\">\\(60^\\circ \\)<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 25%;\">\\({\\mathop{\\rm sen}\\nolimits} \\alpha \\)<\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{1}{2}\\)<\/span><\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{{\\sqrt 2 }}{2}\\)<\/span><\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{{\\sqrt 3 }}{2}\\)<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 25%;\">\\(\\cos \\alpha \\)<\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{{\\sqrt 3 }}{2}\\)<\/span><\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{{\\sqrt 2 }}{2}\\)<\/span><\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{1}{2}\\)<\/span><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 25%;\">\\({\\mathop{\\rm tg}\\nolimits} \\alpha \\)<\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\frac{{\\sqrt 3 }}{3}\\)<\/span><\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(1\\)<\/span><\/td>\n<td style=\"width: 25%;\"><span style=\"color: #0000ff;\">\\(\\sqrt 3 \\)<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/blockquote>\n\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_14152' onClick='GTTabs_show(1,14152)'>&lt;&lt; Resolu\u00e7\u00e3o<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Na figura, [DU] \u00e9 uma diagonal do quadrado de lado a. Qual \u00e9 a medida da amplitude do \u00e2ngulo UDA? Justifica. Calcula, a partir do quadrado de lado a, os valores&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":14158,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,489],"tags":[426,491,493,490,492],"series":[],"class_list":["post-14152","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-trigonometria-9--ano","tag-9-o-ano","tag-cosseno","tag-razao-trigonometrica","tag-seno","tag-tangente"],"views":1808,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/03\/9V2Pag057-6a.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/14152","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=14152"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/14152\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/14158"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=14152"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=14152"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=14152"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=14152"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}