{"id":13502,"date":"2018-02-05T22:01:38","date_gmt":"2018-02-05T22:01:38","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=13502"},"modified":"2022-01-16T15:21:09","modified_gmt":"2022-01-16T15:21:09","slug":"com-uma-folha-de-papel","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=13502","title":{"rendered":"Com uma folha de papel&#8230;"},"content":{"rendered":"<p><ul id='GTTabs_ul_13502' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_13502' class='GTTabs_curr'><a  id=\"13502_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_13502' ><a  id=\"13502_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_13502'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"13503\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=13503\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png\" data-orig-size=\"350,225\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Folha de papel\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png\" class=\"alignright size-medium wp-image-13503\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6-300x193.png\" alt=\"\" width=\"300\" height=\"193\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6-300x193.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png 350w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a>Com uma folha de papel pode construir-se a superf\u00edcie lateral de um cilindro, como v\u00eas na figura.<\/p>\n<ol>\n<li>Determina o raio da base desse cilindro, arredondado \u00e0s d\u00e9cimas.<\/li>\n<li>Se se recortasse um c\u00edrculo de modo a obter uma base para o cilindro, qual seria a capacidade da embalagem obtida, em litros?<br \/>\nApresenta o resultado arredondado \u00e0s d\u00e9cimas.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_13502' onClick='GTTabs_show(1,13502)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_13502'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"13503\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=13503\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png\" data-orig-size=\"350,225\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Folha de papel\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png\" class=\"alignright size-medium wp-image-13503\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6-300x193.png\" alt=\"\" width=\"300\" height=\"193\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6-300x193.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag011-6.png 350w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a>O comprimento do raio da base do cilindro \u00e9 \\(r = \\frac{{21,5}}{{2\\pi }} \\approx 3,4\\) cm.<br \/>\n\u00ad<\/li>\n<li>O volume do cilindro, em cent\u00edmetros c\u00fabicos, \u00e9:<br \/>\n\\[{V_{Cilindro}} = \\left( {\\pi \\times {{\\left( {\\frac{{21,5}}{{2\\pi }}} \\right)}^2}} \\right) \\times 31,4 = \\frac{{{{21,5}^2} \\times 31,4}}{{4\\pi }} \\approx 1155,0\\]<br \/>\nPortanto, a capacidade da embalagem seria de \\({1155,0^{c{m^3}}} = {1,1550^{dm{}^3}} \\approx {1,2^l}\\), aproximadamente.<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_13502' onClick='GTTabs_show(0,13502)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Com uma folha de papel pode construir-se a superf\u00edcie lateral de um cilindro, como v\u00eas na figura. Determina o raio da base desse cilindro, arredondado \u00e0s d\u00e9cimas. Se se recortasse um&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":20371,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,466],"tags":[426,469,109],"series":[],"class_list":["post-13502","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-distancias-areas-e-volumes-de-solidos","tag-9-o-ano","tag-cilindro","tag-volume"],"views":1842,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V2Pag016-6_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/13502","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=13502"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/13502\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20371"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=13502"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=13502"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=13502"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=13502"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}