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{"id":13461,"date":"2018-02-04T17:57:04","date_gmt":"2018-02-04T17:57:04","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=13461"},"modified":"2022-01-17T16:20:22","modified_gmt":"2022-01-17T16:20:22","slug":"na-figura-esta-representada-uma-circunferencia","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=13461","title":{"rendered":"Na figura est\u00e1 representada uma circunfer\u00eancia"},"content":{"rendered":"<p><ul id='GTTabs_ul_13461' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_13461' class='GTTabs_curr'><a  id=\"13461_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_13461' ><a  id=\"13461_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_13461'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"13462\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=13462\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\" data-orig-size=\"210,245\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Circunfer\u00eancia\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\" class=\"alignright size-full wp-image-13462\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\" alt=\"\" width=\"210\" height=\"245\" \/><\/a>Na figura est\u00e1 representada uma circunfer\u00eancia.<\/p>\n<p>Sabe-se que:<\/p>\n<ul>\n<li>[AC] \u00e9 um di\u00e2metro de comprimento 15;<\/li>\n<li>B \u00e9 um ponto da circunfer\u00eancia.<\/li>\n<li>\\(\\overline {AB} = 12\\)<\/li>\n<\/ul>\n<ol>\n<li>Justifica que o tri\u00e2ngulo [ABC] \u00e9 ret\u00e2ngulo em B.<\/li>\n<li>Calcula a \u00e1rea da regi\u00e3o sombreada a laranja na figura.<br \/>\nApresenta os c\u00e1lculos que efetuares e, na tua resposta, escreve o resultado arredondado \u00e0s unidades.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_13461' onClick='GTTabs_show(1,13461)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_13461'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ul>\n<li>\n<blockquote>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"13462\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=13462\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\" data-orig-size=\"210,245\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Circunfer\u00eancia\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\" class=\"alignright size-full wp-image-13462\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3.png\" alt=\"\" width=\"210\" height=\"245\" \/><\/a>[AC] \u00e9 um di\u00e2metro de comprimento 15;<\/p>\n<\/blockquote>\n<\/li>\n<li>\n<blockquote>\n<p>B \u00e9 um ponto da circunfer\u00eancia.<\/p>\n<\/blockquote>\n<\/li>\n<li>\n<blockquote>\n<p>\\(\\overline {AB} = 12\\)<\/p>\n<\/blockquote>\n<\/li>\n<\/ul>\n<ol>\n<li>Como [AC] \u00e9 um di\u00e2metro, ent\u00e3o o \u00e2ngulo ABC est\u00e1 escrito num arco de semicircunfer\u00eancia. Consequentemente, este \u00e2ngulo \u00e9 ret\u00e2ngulo, pois \\(A\\widehat BC = \\frac{{\\overparen{AC}}}{2} = \\frac{{180^\\circ }}{2} = 90^\\circ \\).<br \/>\n\u00ad<\/li>\n<li>Aplicando o Teorema de Pit\u00e1goras no tri\u00e2ngulo ret\u00e2ngulo [ABC], temos:<br \/>\n\\[\\overline {BC} = \\sqrt {{{\\overline {AC} }^2} &#8211; {{\\overline {AB} }^2}} = \\sqrt {{{15}^2} &#8211; {{12}^2}} = \\sqrt {81} = 9\\]<br \/>\nPortanto, a \u00e1rea (em u.a.) da regi\u00e3o sombreada a laranja na figura \u00e9:<br \/>\n\\[\\begin{array}{*{20}{l}}{{A_{Sombreada}}}&amp; = &amp;{{A_\\bigcirc } &#8211; {A_{\\left[ {ABC} \\right]}}}\\\\{}&amp; = &amp;{\\pi \\times {{\\left( {{\\textstyle{{15} \\over 2}}} \\right)}^2} &#8211; \\frac{{12 \\times 9}}{2}}\\\\{}&amp; = &amp;{\\frac{{225\\pi &#8211; 216}}{4}}\\\\{}&amp; \\approx &amp;{123}\\end{array}\\]<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_13461' onClick='GTTabs_show(0,13461)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Na figura est\u00e1 representada uma circunfer\u00eancia. Sabe-se que: [AC] \u00e9 um di\u00e2metro de comprimento 15; B \u00e9 um ponto da circunfer\u00eancia. \\(\\overline {AB} = 12\\) Justifica que o tri\u00e2ngulo [ABC] \u00e9&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":20504,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,278],"tags":[426,280,188],"series":[],"class_list":["post-13461","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-circunferencia-e-poligonos","tag-9-o-ano","tag-angulo-inscrito","tag-circunferencia"],"views":2846,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2018\/02\/9V1Pag149-3_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/13461","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=13461"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/13461\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20504"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=13461"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=13461"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=13461"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=13461"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}