\nEnunciado<\/b><\/span><\/p>\n
Resolve a inequa\u00e7\u00e3o seguinte:<\/p>\n
\\[{\\frac{{12}}{5}x – 4 \\ge \\frac{5}{2}\\left( {x – 3} \\right)}\\]<\/p>\n
Apresenta o conjunto-solu\u00e7\u00e3o na forma de um intervalo de n\u00fameros reais.
\nApresenta todos os c\u00e1lculos que efetuares.<\/p>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
\\[\\begin{array}{*{20}{l}}{\\frac{{12}}{{\\mathop 5\\limits_{\\left( 2 \\right)} }}x – \\mathop 4\\limits_{\\left( {10} \\right)} \\ge \\frac{5}{{\\mathop 2\\limits_{\\left( 5 \\right)} }}\\left( {x – 3} \\right)}& \\Leftrightarrow &{24x – 40 \\ge 25x – 75}\\\\{}& \\Leftrightarrow &{ – x \\ge – 35}\\\\{}& \\Leftrightarrow &{x \\le 35}\\\\{}&{}&{}\\\\{}&{}&{S = \\left] { – \\infty ,\\;35} \\right]}\\end{array}\\]<\/p>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Resolve a inequa\u00e7\u00e3o seguinte: \\[{\\frac{{12}}{5}x – 4 \\ge \\frac{5}{2}\\left( {x – 3} \\right)}\\] Apresenta o conjunto-solu\u00e7\u00e3o na forma de um intervalo de n\u00fameros reais. Apresenta todos os c\u00e1lculos que efetuares. Resolu\u00e7\u00e3o...<\/p>\n","protected":false},"author":1,"featured_media":19189,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,258],"tags":[270,445],"series":[],"class_list":["post-12950","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-os-numeros-reais","tag-inequacao","tag-intervalo-de-numeros-reais"],"views":2650,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat75.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/12950","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=12950"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/12950\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19189"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=12950"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=12950"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=12950"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=12950"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}