{"id":12924,"date":"2017-10-31T19:01:44","date_gmt":"2017-10-31T19:01:44","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=12924"},"modified":"2022-01-16T00:58:51","modified_gmt":"2022-01-16T00:58:51","slug":"uma-caixa-paralelepipedica","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=12924","title":{"rendered":"Uma caixa paralelepip\u00e9dica"},"content":{"rendered":"<p><ul id='GTTabs_ul_12924' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_12924' class='GTTabs_curr'><a  id=\"12924_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_12924' ><a  id=\"12924_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_12924'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"12927\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=12927\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png\" data-orig-size=\"579,206\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Caixas\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png\" class=\"alignright wp-image-12927 size-medium\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas-300x107.png\" alt=\"\" width=\"300\" height=\"107\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas-300x107.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png 579w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a>Uma caixa paralelepip\u00e9dica tem 15 cm de comprimento, 12 cm de largura e 5 cm de altura.<\/p>\n<p>A Rosa quer construir uma outra caixa, com a mesma largura e a mesma altura desta, mas com mais de 1200 cm<sup>3<\/sup> de volume.<\/p>\n<p>Quantos cent\u00edmetros, no m\u00ednimo, dever\u00e1 ter o comprimento da nova caixa, sabendo que a Rosa pretende que seja um n\u00famero inteiro?<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_12924' onClick='GTTabs_show(1,12924)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_12924'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"12927\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=12927\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png\" data-orig-size=\"579,206\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"Caixas\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png\" class=\"alignright wp-image-12927 size-medium\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas-300x107.png\" alt=\"\" width=\"300\" height=\"107\" srcset=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas-300x107.png 300w, https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Caixas.png 579w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\" \/><\/a>Seja\u00a0\\(x\\) o comprimento da nova caixa, em cent\u00edmetros, e\u00a0\\(V\\) o seu volume, em cent\u00edmetros c\u00fabicos.<\/p>\n<p>Assim, temos:<\/p>\n<p>\\[\\begin{array}{*{20}{l}}{V &gt; 1200}&amp; \\Leftrightarrow &amp;{x \\times 12 \\times 5 &gt; 1200}\\\\{}&amp; \\Leftrightarrow &amp;{60x &gt; 1200}\\\\{}&amp; \\Leftrightarrow &amp;{x &gt; 20}\\end{array}\\]<\/p>\n<p>Como a Rosa imp\u00f4s que\u00a0o comprimento (em cent\u00edmetros) da caixa seja um n\u00famero inteiro, ent\u00e3o o comprimento da caixa dever\u00e1 ser 21 cm, no m\u00ednimo.<\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_12924' onClick='GTTabs_show(0,12924)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Uma caixa paralelepip\u00e9dica tem 15 cm de comprimento, 12 cm de largura e 5 cm de altura. A Rosa quer construir uma outra caixa, com a mesma largura e a mesma&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":20329,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,258],"tags":[270,445],"series":[],"class_list":["post-12924","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-os-numeros-reais","tag-inequacao","tag-intervalo-de-numeros-reais"],"views":1762,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/9V1Pag037-20_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/12924","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=12924"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/12924\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20329"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=12924"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=12924"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=12924"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=12924"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}