{"id":12912,"date":"2017-10-31T00:50:46","date_gmt":"2017-10-31T00:50:46","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=12912"},"modified":"2022-01-16T00:42:10","modified_gmt":"2022-01-16T00:42:10","slug":"um-circulo-com-determinada-area","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=12912","title":{"rendered":"Um c\u00edrculo com determinada \u00e1rea"},"content":{"rendered":"<p><ul id='GTTabs_ul_12912' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_12912' class='GTTabs_curr'><a  id=\"12912_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_12912' ><a  id=\"12912_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_12912'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Um c\u00edrculo tem 9,42 dm<sup>2<\/sup> de \u00e1rea.<\/p>\n<p>Determina valores aproximados a menos de uma cent\u00e9sima, um por defeito e outro por excesso, do per\u00edmetro desse c\u00edrculo.<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_12912' onClick='GTTabs_show(1,12912)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_12912'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<p>Conv\u00e9m recordar:\u00a0\\({A_\\bigcirc } = \\pi {r^2}\\) e\u00a0\\({P_\\bigcirc } = 2\\pi r\\).<\/p>\n<p>Comecemos por exprimir o raio do c\u00edrculo em fun\u00e7\u00e3o da sua \u00e1rea:<\/p>\n<p>\\[r = \\sqrt {\\frac{{9,42}}{\\pi }} \\]<\/p>\n<p>Assim, o per\u00edmetro do c\u00edrculo pode ser expresso por:<\/p>\n<p>\\[{P_\\bigcirc } = 2\\pi \\sqrt {\\frac{{9,42}}{\\pi }} = \\sqrt {\\frac{{4{\\pi ^2} \\times 9,42}}{\\pi }} = \\sqrt {37,68 \\times \\pi } \\]<\/p>\n<p><a href=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Calculo5.png\"><img loading=\"lazy\" decoding=\"async\" data-attachment-id=\"12915\" data-permalink=\"https:\/\/www.acasinhadamatematica.pt\/?attachment_id=12915\" data-orig-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Calculo5.png\" data-orig-size=\"198,134\" data-comments-opened=\"1\" data-image-meta=\"{&quot;aperture&quot;:&quot;0&quot;,&quot;credit&quot;:&quot;&quot;,&quot;camera&quot;:&quot;&quot;,&quot;caption&quot;:&quot;&quot;,&quot;created_timestamp&quot;:&quot;0&quot;,&quot;copyright&quot;:&quot;&quot;,&quot;focal_length&quot;:&quot;0&quot;,&quot;iso&quot;:&quot;0&quot;,&quot;shutter_speed&quot;:&quot;0&quot;,&quot;title&quot;:&quot;&quot;,&quot;orientation&quot;:&quot;0&quot;}\" data-image-title=\"C\u00e1lculo\" data-image-description=\"\" data-image-caption=\"\" data-large-file=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Calculo5.png\" class=\"alignright size-full wp-image-12915\" src=\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/Calculo5.png\" alt=\"\" width=\"198\" height=\"134\" \/><\/a>Utilizando uma calculadora, obtemos:<\/p>\n<p>\\[10,88 &lt; \\sqrt {37,68 \\times \\pi } &lt; 10,89\\]<\/p>\n<p>Logo, um enquadramento do per\u00edmetro do c\u00edrculo \u00e9:\u00a0\\(10,88\\;dm &lt; {P_\\bigcirc } &lt; 10,89\\;dm\\).<\/p><\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_12912' onClick='GTTabs_show(0,12912)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Um c\u00edrculo tem 9,42 dm2 de \u00e1rea. Determina valores aproximados a menos de uma cent\u00e9sima, um por defeito e outro por excesso, do per\u00edmetro desse c\u00edrculo. Resolu\u00e7\u00e3o &gt;&gt; Resolu\u00e7\u00e3o &lt;&lt; Enunciado<\/p>\n","protected":false},"author":1,"featured_media":20324,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[213,97,258],"tags":[443,442],"series":[],"class_list":["post-12912","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-9--ano","category-aplicando","category-os-numeros-reais","tag-enquadramento","tag-valor-aproximado"],"views":1713,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2017\/10\/9V1Pag036-12_520x245.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/12912","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=12912"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/12912\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/20324"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=12912"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=12912"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=12912"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=12912"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}