O gr\u00e1fico da fun\u00e7\u00e3o ${f\\left( x \\right) = H\\left( x \\right) – 2}$ pode ser obtido a partir do gr\u00e1fico da fun\u00e7\u00e3o $H$ por transla\u00e7\u00e3o associada ao vetor $\\overrightarrow u\u00a0 = \\left( {0, – 2} \\right)$.
\n\\[\\begin{array}{*{20}{c}}
\n{f\\left( x \\right) = H\\left( x \\right) – 2 = \\left\\{ {\\begin{array}{*{20}{c}}
\n{0 – 2}& \\Leftarrow &{x < 0} \\\\
\n{\\frac{1}{2} – 2}& \\Leftarrow &{x = 0} \\\\
\n{1 – 2}& \\Leftarrow &{x > 0}
\n\\end{array}} \\right.}& = &{\\left\\{ {\\begin{array}{*{20}{c}}
\n{ – 2}& \\Leftarrow &{x < 0} \\\\
\n{ – \\frac{3}{2}}& \\Leftarrow &{x = 0} \\\\
\n{ – 1}& \\Leftarrow &{x > 0}
\n\\end{array}} \\right.}
\n\\end{array}\\]<\/p>\nO gr\u00e1fico da fun\u00e7\u00e3o ${g\\left( x \\right) = H\\left( {x + 2} \\right)}$ pode ser obtido a partir do gr\u00e1fico da fun\u00e7\u00e3o $H$ por transla\u00e7\u00e3o associada ao vetor $\\overrightarrow v\u00a0 = \\left( { – 2,0} \\right)$.
\n\\[\\begin{array}{*{20}{c}}
\n{g\\left( x \\right) = H\\left( {x + 2} \\right) = \\left\\{ {\\begin{array}{*{20}{c}}
\n0& \\Leftarrow &{x + 2 < 0} \\\\
\n{\\frac{1}{2}}& \\Leftarrow &{x + 2 = 0} \\\\
\n1& \\Leftarrow &{x + 2 > 0}
\n\\end{array}} \\right.}& = &{\\left\\{ {\\begin{array}{*{20}{c}}
\n0& \\Leftarrow &{x <\u00a0 – 2} \\\\
\n{\\frac{1}{2}}& \\Leftarrow &{x =\u00a0 – 2} \\\\
\n1& \\Leftarrow &{x >\u00a0 – 2}
\n\\end{array}} \\right.}
\n\\end{array}\\]<\/p>\n
O gr\u00e1fico da fun\u00e7\u00e3o ${r\\left( x \\right) =\u00a0 – 3H\\left( { – x} \\right) + 4}$ pode ser obtido a partir do gr\u00e1fico da fun\u00e7\u00e3o $H$ pela seguinte sequ\u00eancia de transforma\u00e7\u00f5es:<\/p>\n<\/li>\n<\/ol>\n
![\"Oliver](\"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2014\/02\/Oliver_Heaviside2.jpg\")
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