{"id":11758,"date":"2014-02-05T02:40:45","date_gmt":"2014-02-05T02:40:45","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=11758"},"modified":"2022-01-14T18:57:29","modified_gmt":"2022-01-14T18:57:29","slug":"considere-a-funcao-h","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=11758","title":{"rendered":"Considere a fun\u00e7\u00e3o $h$"},"content":{"rendered":"<p><ul id='GTTabs_ul_11758' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_11758' class='GTTabs_curr'><a  id=\"11758_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_11758' ><a  id=\"11758_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_11758'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Considere a fun\u00e7\u00e3o $h$, definida por: \\[h\\left( x \\right) = \\frac{{2{x^2} + x &#8211; 1}}{{x &#8211; 3}}\\]<\/p>\n<ol>\n<li>Escreva $h\\left( x \\right)$ na forma \\[a + bx + \\frac{c}{{x &#8211; 3}}\\]<\/li>\n<li>A partir da decomposi\u00e7\u00e3o obtida na al\u00ednea anterior, determine:<br \/>\n<table style=\"border-collapse: collapse; width: 100%;\">\n<tbody>\n<tr>\n<td style=\"width: 33.3333%;\">\\[\\mathop {\\lim }\\limits_{x \\to\u00a0 + \\infty } h\\left( x \\right)\\]<\/td>\n<td style=\"width: 33.3333%;\">\\[\\mathop {\\lim }\\limits_{x \\to\u00a0 &#8211; \\infty } h\\left( x \\right)\\]<\/td>\n<td style=\"width: 33.3333%;\">\\[\\mathop {\\lim }\\limits_{x \\to 3} h\\left( x \\right)\\]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/li>\n<li>Tendo em considera\u00e7\u00e3o os resultados obtidos anteriormente, esboce o gr\u00e1fico da fun\u00e7\u00e3o.<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_11758' onClick='GTTabs_show(1,11758)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_11758'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>\u00a0\\[\\begin{array}{*{20}{r}}<br \/>\n{2{x^2}}&amp;{ + x}&amp;{ &#8211; 1}&amp;{}&amp;x&amp;{ &#8211; 3} \\\\<br \/>\n{ &#8211; 2{x^2}}&amp;{ + 6x}&amp;{}&amp;{}&amp;{2x}&amp;{ + 7} \\\\<br \/>\n\\hline<br \/>\n{}&amp;{7x}&amp;{ &#8211; 1}&amp;{}&amp;{}&amp;{} \\\\<br \/>\n{}&amp;{ &#8211; 7x}&amp;{ + 21}&amp;{}&amp;{}&amp;{} \\\\<br \/>\n\\hline<br \/>\n{}&amp;{}&amp;{20}&amp;{}&amp;{}&amp;{}<br \/>\n\\end{array}\\]<\/p>\n<p>Tendo em considera\u00e7\u00e3o a divis\u00e3o acima, temos: \\[h\\left( x \\right) = \\frac{{2{x^2} + x &#8211; 1}}{{x &#8211; 3}} = 2x + 7 + \\frac{{20}}{{x &#8211; 3}}\\]<br \/>\n\u00ad<\/p>\n<\/li>\n<li>Se $x \\to\u00a0 + \\infty $, ent\u00e3o $\\frac{{20}}{{x &#8211; 3}} \\to {0^ + }$, $2x + 7 \\to\u00a0 + \\infty $ e, consequentemente, $h\\left( x \\right) = 2x + 7 + \\frac{{20}}{{x &#8211; 3}} \\to\u00a0 + \\infty $.<br \/>\nIsto \u00e9: \\[\\mathop {\\lim }\\limits_{x \\to\u00a0 + \\infty } h\\left( x \\right) =\u00a0 + \\infty \\]<br \/>\nLogo, o gr\u00e1fico de $h$ n\u00e3o possui ass\u00edntota horizontal quando $x \\to\u00a0 + \\infty $.<br \/>\nNo entanto, $y = 2x + 7$ \u00e9 a equa\u00e7\u00e3o reduzida de uma ass\u00edntota obl\u00edqua do gr\u00e1fico de $h$ quando $x \\to\u00a0 + \\infty $.<\/p>\n<p>De forma an\u00e1loga, conclui-se que \\[\\mathop {\\lim }\\limits_{x \\to\u00a0 &#8211; \\infty } h\\left( x \\right) =\u00a0 &#8211; \\infty \\]<br \/>\nLogo, o gr\u00e1fico de $h$ n\u00e3o possui ass\u00edntota horizontal quando $x \\to\u00a0 &#8211; \\infty $.<br \/>\nNo entanto, $y = 2x + 7$ \u00e9\u00a0a equa\u00e7\u00e3o reduzida de uma ass\u00edntota obl\u00edqua do gr\u00e1fico de $h$ quando $x \\to\u00a0 &#8211; \\infty $.<\/p>\n<p>Se $x \\to {3^ &#8211; }$, ent\u00e3o $\\frac{{20}}{{x &#8211; 3}} \\to\u00a0 &#8211; \\infty $ e, consequentemente, $h\\left( x \\right) = 2x + 7 + \\frac{{20}}{{x &#8211; 3}} \\to\u00a0 &#8211; \\infty $.<br \/>\nIsto \u00e9: \\[\\mathop {\\lim }\\limits_{x \\to {3^ &#8211; }} h\\left( x \\right) =\u00a0 &#8211; \\infty \\]<br \/>\nDe forma an\u00e1loga, conclui-se que \\[\\mathop {\\lim }\\limits_{x \\to {3^ + }} h\\left( x \\right) =\u00a0 + \\infty \\]<br \/>\nLogo, a reta de equa\u00e7\u00e3o $x = 3$ \u00e9 uma equa\u00e7\u00e3o da ass\u00edntota vertical (bilateral)\u00a0do gr\u00e1fico de $h$ quando $x \\to 3$.<br \/>\n\u00ad<\/p>\n<\/li>\n<li><\/li>\n<\/ol>\n<p style=\"text-align: center;\"><script src=\"https:\/\/cdn.geogebra.org\/apps\/deployggb.js\"><\/script>\r\n<div id=\"ggbApplet\" style=\"margin: 0 auto;\"><\/div>\r\n<script>\r\nvar parameters = {\r\n\"id\": 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