{"id":11731,"date":"2014-02-01T22:52:23","date_gmt":"2014-02-01T22:52:23","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=11731"},"modified":"2021-12-26T02:47:32","modified_gmt":"2021-12-26T02:47:32","slug":"resolva-em-mathbbr-as-seguintes-inequacoes","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=11731","title":{"rendered":"Resolva, em $\\mathbb{R}$, as seguintes inequa\u00e7\u00f5es"},"content":{"rendered":"<p><ul id='GTTabs_ul_11731' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_11731' class='GTTabs_curr'><a  id=\"11731_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_11731' ><a  id=\"11731_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_11731'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Resolva, em $\\mathbb{R}$, as seguintes inequa\u00e7\u00f5es:<\/p>\n<ol>\n<li>\\[\\frac{{3x + 2}}{{x + 3}} &gt;\u00a0 &#8211; \\frac{2}{3}\\]<\/li>\n<li>\\[\\frac{{x + 1}}{{x &#8211; 1}} &#8211; \\frac{{x &#8211; 1}}{{x + 1}} &gt; 0\\]<\/li>\n<li>\\[\\frac{{a &#8211; 2}}{a} &lt; \\frac{{a &#8211; 4}}{{a &#8211; 6}}\\]<\/li>\n<\/ol>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_11731' onClick='GTTabs_show(1,11731)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_11731'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<ol>\n<li>Tem-se sucessivamente:<br \/>\n\\[\\begin{array}{*{20}{l}}<br \/>\n{\\frac{{3x + 2}}{{\\mathop {x + 3}\\limits_{\\left( 3 \\right)} }} &gt;\u00a0 &#8211; \\frac{2}{{\\mathop 3\\limits_{\\left( {x + 3} \\right)} }}}&amp; \\Leftrightarrow &amp;{\\frac{{9x + 6 + 2x + 6}}{{3\\left( {x + 3} \\right)}} &gt; 0} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\frac{{11x + 12}}{{3\\left( {x + 3} \\right)}} &gt; 0} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{11x + 2 &gt; 0} \\\\<br \/>\n{3\\left( {x + 3} \\right) &gt; 0}<br \/>\n\\end{array}} \\right.}&amp; \\vee &amp;{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{11x + 2 &lt; 0} \\\\<br \/>\n{3\\left( {x + 3} \\right) &lt; 0}<br \/>\n\\end{array}} \\right.}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{x &gt;\u00a0 &#8211; \\frac{2}{{11}}} \\\\<br \/>\n{x &gt;\u00a0 &#8211; 3}<br \/>\n\\end{array}} \\right.}&amp; \\vee &amp;{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{x &lt;\u00a0 &#8211; \\frac{2}{{11}}} \\\\<br \/>\n{x &lt;\u00a0 &#8211; 3}<br \/>\n\\end{array}} \\right.}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{x &gt;\u00a0 &#8211; \\frac{2}{{11}}}&amp; \\vee &amp;{x &lt;\u00a0 &#8211; 3}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{x \\in \\left] { &#8211; \\infty , &#8211; 3} \\right[ \\cup \\left] { &#8211; \\frac{2}{{11}}, + \\infty } \\right[}<br \/>\n\\end{array}\\]<\/li>\n<li>Tem-se sucessivamente:<br \/>\n\\[\\begin{array}{*{20}{l}}<br \/>\n{\\frac{{x + 1}}{{\\mathop {x &#8211; 1}\\limits_{\\left( {x + 1} \\right)} }} &#8211; \\frac{{x &#8211; 1}}{{\\mathop {x + 1}\\limits_{\\left( {x &#8211; 1} \\right)} }} &gt; 0}&amp; \\Leftrightarrow &amp;{\\frac{{{x^2} + 2x + 1 &#8211; {x^2} + 1}}{{\\left( {x &#8211; 1} \\right)\\left( {x + 1} \\right)}} &gt; 0} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\frac{{2x}}{{\\left( {x &#8211; 1} \\right)\\left( {x + 1} \\right)}} &gt; 0} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{2x &gt; 0} \\\\<br \/>\n{\\left( {x &#8211; 1} \\right)\\left( {x + 1} \\right) &gt; 0}<br \/>\n\\end{array}} \\right.}&amp; \\vee &amp;{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{2x &lt; 0} \\\\<br \/>\n{\\left( {x &#8211; 1} \\right)\\left( {x + 1} \\right) &lt; 0}<br \/>\n\\end{array}} \\right.}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{x &gt; 0} \\\\<br \/>\n{x \\in \\left] { &#8211; \\infty , &#8211; 1} \\right[ \\cup \\left] {1, + \\infty } \\right[}<br \/>\n\\end{array}} \\right.}&amp; \\vee &amp;{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{x &lt; 0} \\\\<br \/>\n{x \\in \\left] { &#8211; 1,1} \\right[}<br \/>\n\\end{array}} \\right.}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{x \\in \\left] {1, + \\infty } \\right[}&amp; \\vee &amp;{x \\in \\left] { &#8211; 1,0} \\right[}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{x \\in \\left] { &#8211; 1,0} \\right[ \\cup \\left] {1, + \\infty } \\right[}<br \/>\n\\end{array}\\]<\/p>\n<p>Em alternativa, podemos usar um quadro de sinal (a partir da express\u00e3o obtida na 2.\u00aa equival\u00eancia acima):<\/p>\n<\/p>\n<table class=\" aligncenter\" style=\"width: 80%;\" border=\"0\" align=\"center\">\n<tbody>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$x$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: left;\" valign=\"middle\">${ &#8211; \\infty }$<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$-1$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\"><\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\"><\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$1$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: right;\" valign=\"middle\">${ + \\infty }$<\/td>\n<\/tr>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$2x$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$\u00a0&#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$\u00a0&#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$\u00a0&#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$\u00a0+ $<\/td>\n<\/tr>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">${\\left( {x &#8211; 1} \\right)\\left( {x + 1} \\right)}$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">\u00a0$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">\u00a0$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<\/tr>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">${\\frac{{2x}}{{\\left( {x &#8211; 1} \\right)\\left( {x + 1} \\right)}}}$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">n.d.<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center; background-color: #90ee90;\" valign=\"middle\">\u00a0$ + $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">\u00a0$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">n.d.<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center; background-color: #90ee90;\" valign=\"middle\">$ + $<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Portanto, $\\frac{{x + 1}}{{x &#8211; 1}} &#8211; \\frac{{x &#8211; 1}}{{x + 1}} &gt; 0 \\Leftrightarrow x \\in \\left] { &#8211; 1,0} \\right[ \\cup \\left] {1, + \\infty } \\right[$.<\/p>\n<\/p>\n<\/li>\n<li>Tem-se sucessivamente:<br \/>\n\\[\\begin{array}{*{20}{l}}<br \/>\n{\\frac{{a &#8211; 2}}{{\\mathop a\\limits_{\\left( {a &#8211; 6} \\right)} }} &lt; \\frac{{a &#8211; 4}}{{\\mathop {a &#8211; 6}\\limits_{\\left( a \\right)} }}}&amp; \\Leftrightarrow &amp;{\\frac{{{a^2} &#8211; 8a + 12 &#8211; {a^2} + 4a}}{{a\\left( {a &#8211; 6} \\right)}} &lt; 0} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\frac{{ &#8211; 4a + 12}}{{a\\left( {a &#8211; 6} \\right)}} &lt; 0} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{ &#8211; 4a + 12 &gt; 0} \\\\<br \/>\n{a\\left( {a &#8211; 6} \\right) &lt; 0}<br \/>\n\\end{array}} \\right.}&amp; \\vee &amp;{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{ &#8211; 4a + 12 &lt; 0} \\\\<br \/>\n{a\\left( {a &#8211; 6} \\right) &gt; 0}<br \/>\n\\end{array}} \\right.}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{a &lt; 3} \\\\<br \/>\n{a \\in \\left] {0,6} \\right[}<br \/>\n\\end{array}} \\right.}&amp; \\vee &amp;{\\left\\{ {\\begin{array}{*{20}{l}}<br \/>\n{a &gt; 3} \\\\<br \/>\n{x \\in \\left] { &#8211; \\infty ,0} \\right[ \\cup \\left] {6, + \\infty } \\right[}<br \/>\n\\end{array}} \\right.}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{\\begin{array}{*{20}{l}}<br \/>\n{a \\in \\left] {0,3} \\right[}&amp; \\vee &amp;{a \\in \\left] {6, + \\infty } \\right[}<br \/>\n\\end{array}} \\\\<br \/>\n{}&amp; \\Leftrightarrow &amp;{a \\in \\left] {0,3} \\right[ \\cup \\left] {6, + \\infty } \\right[}<br \/>\n\\end{array}\\]<\/p>\n<p>Em alternativa, podemos usar um quadro de sinal (a partir da express\u00e3o obtida na 2.\u00aa equival\u00eancia acima):<\/p>\n<\/p>\n<table class=\" aligncenter\" style=\"width: 80%;\" border=\"0\" align=\"center\">\n<tbody>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$a$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: left;\" valign=\"middle\">${ &#8211; \\infty }$<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\"><\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$3$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\"><\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$6$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: right;\" valign=\"middle\">${ + \\infty }$<\/td>\n<\/tr>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">${ &#8211; 4a + 12}$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$\u00a0+ $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$\u00a0+ $<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$\u00a0+ $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$\u00a0&#8211; $<\/td>\n<\/tr>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">${a\\left( {a &#8211; 6} \\right)}$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">\u00a0$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">\u00a0$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<\/tr>\n<tr>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">${\\frac{{ &#8211; 4a + 12}}{{a\\left( {a &#8211; 6} \\right)}}}$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">$ + $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">n.d.<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center; background-color: #90ee90;\" valign=\"middle\">\u00a0$ &#8211; $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">$0$<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center;\" valign=\"middle\">\u00a0$\u00a0+ $<\/td>\n<td style=\"border: 1px solid #000000; width: 20px; text-align: center;\" valign=\"middle\">n.d.<\/td>\n<td style=\"border: 1px solid #000000; width: 80px; text-align: center; background-color: #90ee90;\" valign=\"middle\">$\u00a0&#8211; $<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Portanto, $\\frac{{a &#8211; 2}}{a} &lt; \\frac{{a &#8211; 4}}{{a &#8211; 6}} \\Leftrightarrow a \\in \\left] {0,3} \\right[ \\cup \\left] {6, + \\infty } \\right[$.<\/p>\n<\/li>\n<\/ol>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_11731' onClick='GTTabs_show(0,11731)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Resolva, em $\\mathbb{R}$, as seguintes inequa\u00e7\u00f5es: \\[\\frac{{3x + 2}}{{x + 3}} &gt;\u00a0 &#8211; \\frac{2}{3}\\] \\[\\frac{{x + 1}}{{x &#8211; 1}} &#8211; \\frac{{x &#8211; 1}}{{x + 1}} &gt; 0\\] \\[\\frac{{a &#8211; 2}}{a} &lt;&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":19421,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[98,97,125],"tags":[422,131,270],"series":[],"class_list":["post-11731","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-11--ano","category-aplicando","category-funcoes-racionais","tag-11-o-ano","tag-funcoes-racionais-2","tag-inequacao"],"views":1831,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Inequacao_11c.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/11731","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=11731"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/11731\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19421"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=11731"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=11731"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=11731"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=11731"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}