\nEnunciado<\/b><\/span><\/p>\n
Calcula o n\u00famero designado por cada uma das seguintes pot\u00eancias:<\/p>\n
\n
\u00a0${2^4}$<\/li>\n
${3^3}$<\/li>\n
${0^{75}}$<\/li>\n
${\\left( { – 2} \\right)^4}$<\/li>\n
${\\left( { – 3} \\right)^2}$<\/li>\n
${\\left( { – 1} \\right)^{101}}$<\/li>\n
${\\left( { – 2} \\right)^5}$<\/li>\n
${\\left( { – 3} \\right)^3}$<\/li>\n
${\\left( { – 1} \\right)^{98}}$<\/li>\n
${4^3}$<\/li>\n
${\\left( { – 10} \\right)^3}$<\/li>\n
${10^7}$<\/li>\n<\/ol>\n
Resolu\u00e7\u00e3o >><\/a><\/span><\/div><\/div>\n\n
\nResolu\u00e7\u00e3o<\/b><\/span><\/p>\n
O valor de cada uma das pot\u00eancias poder\u00e1 (e dever\u00e1) ser calculado mentalmente.
\nNo entanto, para recordar o processo de c\u00e1lculo, apresentam-se os mesmos:<\/p>\n
\n
${2^4} = 2 \\times 2 \\times 2 \\times 2 = 16$
\n\u00ad<\/li>\n
${3^3} = 3 \\times 3 \\times 3 = 27$
\n\u00ad<\/li>\n
${0^{75}} = \\underbrace {0 \\times 0 \\times\u00a0 \\cdots\u00a0 \\times 0}_{{\\text{75 fatores}}} = 0$
\n\u00ad<\/li>\n
${\\left( { – 2} \\right)^4} = \\left( { – 2} \\right) \\times \\left( { – 2} \\right) \\times \\left( { – 2} \\right) \\times \\left( { – 2} \\right) = 16$
\n\u00ad<\/li>\n
${\\left( { – 3} \\right)^2} = \\left( { – 3} \\right) \\times \\left( { – 3} \\right) = 9$
\n\u00ad<\/li>\n
${\\left( { – 1} \\right)^{101}} = \\underbrace {\\left( { – 1} \\right) \\times \\left( { – 1} \\right) \\times\u00a0 \\ldots\u00a0 \\times \\left( { – 1} \\right)}_{{\\text{101 fatores}}} =\u00a0 – 1$
\n\u00ad<\/li>\n
${\\left( { – 2} \\right)^5} = \\left( { – 2} \\right) \\times \\left( { – 2} \\right) \\times \\left( { – 2} \\right) \\times \\left( { – 2} \\right) \\times \\left( { – 2} \\right) =\u00a0 – 32$
\n\u00ad<\/li>\n
${\\left( { – 3} \\right)^3} = \\left( { – 3} \\right) \\times \\left( { – 3} \\right) \\times \\left( { – 3} \\right) =\u00a0 – 27$
\n\u00ad<\/li>\n
${\\left( { – 1} \\right)^{98}} = \\underbrace {\\left( { – 1} \\right) \\times \\left( { – 1} \\right) \\times\u00a0 \\ldots\u00a0 \\times \\left( { – 1} \\right)}_{{\\text{98 fatores}}} = 1$
\n\u00ad<\/li>\n
${4^3} = 4 \\times 4 \\times 4 = 64$
\n\u00ad<\/li>\n
${\\left( { – 10} \\right)^3} = \\left( { – 10} \\right) \\times \\left( { – 10} \\right) \\times \\left( { – 10} \\right) =\u00a0 – 1000$
\n\u00ad<\/li>\n
${10^7} = 10 \\times 10 \\times\u00a0 \\cdots\u00a0 \\times 10 = 10000000$<\/li>\n<\/ol>\n
<< Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"
Enunciado Resolu\u00e7\u00e3o Enunciado Calcula o n\u00famero designado por cada uma das seguintes pot\u00eancias: \u00a0${2^4}$ ${3^3}$ ${0^{75}}$ ${\\left( { – 2} \\right)^4}$ ${\\left( { – 3} \\right)^2}$ ${\\left( { – 1} \\right)^{101}}$ ${\\left( { –...<\/p>\n","protected":false},"author":1,"featured_media":19307,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[317,97,318],"tags":[428,142],"series":[],"class_list":["post-10648","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-7-o-ano","category-aplicando","category-numeros-inteiros","tag-7-o-ano","tag-potencias"],"views":2139,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat112.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/10648","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=10648"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/10648\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19307"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=10648"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=10648"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=10648"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=10648"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}