{"id":10546,"date":"2012-10-15T02:20:27","date_gmt":"2012-10-15T01:20:27","guid":{"rendered":"https:\/\/www.acasinhadamatematica.pt\/?p=10546"},"modified":"2022-01-01T01:05:44","modified_gmt":"2022-01-01T01:05:44","slug":"escolhe-um-numero","status":"publish","type":"post","link":"https:\/\/www.acasinhadamatematica.pt\/?p=10546","title":{"rendered":"Escolhe um n\u00famero"},"content":{"rendered":"<p><ul id='GTTabs_ul_10546' class='GTTabs' style='display:none'>\n<li id='GTTabs_li_0_10546' class='GTTabs_curr'><a  id=\"10546_0\" onMouseOver=\"GTTabsShowLinks('Enunciado'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Enunciado<\/a><\/li>\n<li id='GTTabs_li_1_10546' ><a  id=\"10546_1\" onMouseOver=\"GTTabsShowLinks('Resolu\u00e7\u00e3o'); return true;\"  onMouseOut=\"GTTabsShowLinks();\"  class='GTTabsLinks'>Resolu\u00e7\u00e3o<\/a><\/li>\n<\/ul>\n\n<div class='GTTabs_divs GTTabs_curr_div' id='GTTabs_0_10546'>\n<span class='GTTabs_titles'><b>Enunciado<\/b><\/span><\/p>\n<p>Escolhe um n\u00famero.<\/p>\n<p>Adiciona-lhe $-2$ e triplica a soma obtida.<\/p>\n<p>Subtrai $-7$ ao resultado e divide-o por $-2$.<\/p>\n<p>Ao quociente subtrai $5$.<\/p>\n<p>Que n\u00famero obt\u00e9ns?<\/p>\n<p>Organiza os teus c\u00e1lculos, usando um esquema ou uma tabela, para quatro n\u00fameros \u00e0 tua escolha.<\/p>\n<p><div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_next'><a href='#GTTabs_ul_10546' onClick='GTTabs_show(1,10546)'>Resolu\u00e7\u00e3o &gt;&gt;<\/a><\/span><\/div><\/div>\n\n<div class='GTTabs_divs' id='GTTabs_1_10546'>\n<span class='GTTabs_titles'><b>Resolu\u00e7\u00e3o<\/b><\/span><!--more--><\/p>\n<table border=\"0\" align=\"center\">\n<tbody>\n<tr>\n<td style=\"text-align: right;\">Escolhe um n\u00famero<\/td>\n<td><\/td>\n<td>$4$<\/td>\n<td><\/td>\n<td>$ &#8211; 5$<\/td>\n<td><\/td>\n<td>$ &#8211; 12$<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: right;\">Adiciona-lhe $-2$<\/td>\n<td><\/td>\n<td>$4 + \\left( { &#8211; 2} \\right)$<\/td>\n<td><\/td>\n<td>$ &#8211; 5 + \\left( { &#8211; 2} \\right)$<\/td>\n<td><\/td>\n<td>$ &#8211; 12 + \\left( { &#8211; 2} \\right)$<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: right;\">e triplica a soma obtida<\/td>\n<td><\/td>\n<td>$\\left( {4 + \\left( { &#8211; 2} \\right)} \\right) \\times 3$<\/td>\n<td><\/td>\n<td>$\\left( { &#8211; 5 + \\left( { &#8211; 2} \\right)} \\right) \\times 3$<\/td>\n<td><\/td>\n<td>$\\left( { &#8211; 12 + \\left( { &#8211; 2} \\right)} \\right) \\times 3$<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: right;\">Subtrai $-7$ ao resultado<\/td>\n<td><\/td>\n<td>$\\left( {4 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)$<\/td>\n<td><\/td>\n<td>$\\left( { &#8211; 5 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)$<\/td>\n<td><\/td>\n<td>$\\left( { &#8211; 12 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)$<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: right;\">e divide-o por $-2$<\/td>\n<td><\/td>\n<td>$\\left[ {\\left( {4 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right)$<\/td>\n<td><\/td>\n<td>$\\left[ {\\left( { &#8211; 5 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right)$<\/td>\n<td><\/td>\n<td>$\\left[ {\\left( { &#8211; 12 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right)$<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: right;\">Ao quociente subtrai $5$<\/td>\n<td><\/td>\n<td>$\\left[ {\\left( {4 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5$<\/td>\n<td><\/td>\n<td>$\\left[ {\\left( { &#8211; 5 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5$<\/td>\n<td><\/td>\n<td>$\\left[ {\\left( { &#8211; 12 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5$<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: right;\">Que n\u00famero obt\u00e9ns?<\/td>\n<td><\/td>\n<td style=\"text-align: center;\">$A$<\/td>\n<td><\/td>\n<td style=\"text-align: center;\">$B$<\/td>\n<td><\/td>\n<td style=\"text-align: center;\">$C$<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Vamos agora calcular os n\u00fameros obtidos:<\/p>\n<p>$$\\begin{array}{*{20}{l}} \u00a0 A&amp; = &amp;{\\left[ {\\left( {4 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{\\left[ {2 \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{\\left( {6 + 7} \\right) \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{13 \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{ &#8211; 6,5 &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{ &#8211; 11,5} \\end{array}$$<\/p>\n<p>$$\\begin{array}{*{20}{l}} \u00a0 B&amp; = &amp;{\\left[ {\\left( { &#8211; 5 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{\\left[ { &#8211; 7 \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{\\left( { &#8211; 21 + 7} \\right) \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{ &#8211; 14 \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{7 &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;2 \\end{array}$$<\/p>\n<p>$$\\begin{array}{*{20}{l}} \u00a0 C&amp; = &amp;{\\left[ {\\left( { &#8211; 12 + \\left( { &#8211; 2} \\right)} \\right) \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{\\left[ { &#8211; 14 \\times 3 &#8211; \\left( { &#8211; 7} \\right)} \\right] \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{\\left( { &#8211; 42 + 7} \\right) \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{ &#8211; 35 \\div \\left( { &#8211; 2} \\right) &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{17,5 &#8211; 5} \\\\ \u00a0 {}&amp; = &amp;{12,5} \\end{array}$$<\/p><\/p>\n<div class='GTTabsNavigation' style='display:none'><span class='GTTabs_nav_prev'><a href='#GTTabs_ul_10546' onClick='GTTabs_show(0,10546)'>&lt;&lt; Enunciado<\/a><\/span><\/div><\/div>\n\n","protected":false},"excerpt":{"rendered":"<p>Enunciado Resolu\u00e7\u00e3o Enunciado Escolhe um n\u00famero. Adiciona-lhe $-2$ e triplica a soma obtida. Subtrai $-7$ ao resultado e divide-o por $-2$. Ao quociente subtrai $5$. Que n\u00famero obt\u00e9ns? Organiza os teus c\u00e1lculos, usando um&#46;&#46;&#46;<\/p>\n","protected":false},"author":1,"featured_media":19171,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[317,97,318],"tags":[428,330,320,319],"series":[],"class_list":["post-10546","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-7-o-ano","category-aplicando","category-numeros-inteiros","tag-7-o-ano","tag-divisao","tag-multiplicacao","tag-numeros-inteiros-2"],"views":1701,"jetpack_featured_media_url":"https:\/\/www.acasinhadamatematica.pt\/wp-content\/uploads\/2021\/12\/Mat62.png","jetpack_sharing_enabled":true,"jetpack_likes_enabled":true,"_links":{"self":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/10546","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=10546"}],"version-history":[{"count":0,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/posts\/10546\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=\/wp\/v2\/media\/19171"}],"wp:attachment":[{"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=10546"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=10546"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=10546"},{"taxonomy":"series","embeddable":true,"href":"https:\/\/www.acasinhadamatematica.pt\/index.php?rest_route=%2Fwp%2Fv2%2Fseries&post=10546"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}